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yawa3891 [41]
3 years ago
15

Chemiosmosis uses __________ to supply the energy necessary to phosphorylate adp to atp.

Biology
1 answer:
solniwko [45]3 years ago
8 0
I believe the corre term to fill in the blank is "a protein gradient." Chemiosmosis uses a protein gradient to supply the energy necessary to phosphorylate adp to atp. It<span> is the diffusion of hydrogen ions (protons) across the biological membrane via the ATP synthase.</span>
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During photosynthesis, ___________ is reduced to ___________
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Write an interview with a water molecule. Write a story describing one possible trip that a water molecule could take through th
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Hi! did you get your answer or no if not I have it if you are interested. Have a nice day! ;)
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3 years ago
What is the ultimate source of energy of almost any terrestrial (land) food chain or food web? What process converts this energy
andriy [413]
Hey there!

Here are your answers:

<u><em>1. The proper answer to this question is "the Sun".</em></u>

Reason:

<u><em>The Sun is the ultimate source of energy for organisms it allows plants to use photosynthesis </em></u><span><u><em>to convert light energy into energy for that organisms and other organisms.</em></u>

<em>Therefore the answer is the Sun.</em>

Here is your second answer:

<u><em>2. The proper answer to this question is "</em></u></span><u><em>photosynthesis".</em></u>

Reason:

<u><em>Photosynthesis is the process that plants use to change (convert) light energy into energy (that other organisms can use). For example a apple tree uses </em></u><span><u><em>photosynthesis to make apples for humans, and other organisms to consume for energy.</em></u>

<em>Therefore the answer is </em></span><span><em>photosynthesis!</em>

<em>To sum up the answers are:</em>
<em>1.Sun</em>
<em>2.P</em></span><span><em>hotosynthesis</em>

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit</span>
6 0
3 years ago
Explain why reserves protect<br> biodiversity.
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5 0
2 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
2 years ago
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