The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:
- |t| < 1.9801 -> do not reject the null hypothesis.
- |t| > 1.9801 -> reject the null hypothesis.
<h3>What are the hypothesis tested?</h3>
At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

We have a two-tailed test, as we are testing if the mean is different of a value.
Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:
|t| = 1.9801.
Hence the decision rule is:
- |t| < 1.9801 -> do not reject the null hypothesis.
- |t| > 1.9801 -> reject the null hypothesis.
More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630
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1. 45.8-7.48=38.32 in
2. 5/6-3/4=10/12-9/12= 1/12 miles farther
Answer:
72?-ft
Step-by-step explanation:
The tower shadow is 12 times as long as that of the post, so the tower will be 12 times as high as the post.
... 12 × 6?-ft = 72?-ft
Answer:
7 zeroes
Step-by-step explanation:
I HOPE it will help you
Answer:
Semi-monthly gross pay = $662.5
Step-by-step explanation:
Given:
Earning per hour = $13.25
Number of hours per week = 25 hours
Find:
Semi-monthly gross pay
Computation:
Assume two week in semi-month
So,
Total working hour = 2(25)
Total working hour = 50 hours
Semi-monthly gross pay = Total working hour × Earning per hour
Semi-monthly gross pay = 50 × 13.25
Semi-monthly gross pay = $662.5