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3 years ago

14

A basketball player has already scored 56 points in a game. the team record for points in a game is 72. which equation would all

ow you to find out how many more points the players needs to tie the record?

1 answer:

xxMikexx [17]3 years ago

6 0

72-56= 16. because if the highest points is 72 if you subtract the points they have now you will get 16

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What is Australia constitution

Daniel [21]

Answer :

The Australian Constitution is the set of rules by which Australia is run. It came into effect on 1 January 1901. This fact sheet summarises the key features of the Constitution and how it can be changed. Commonwealth of Australia Constitution Act, 1900: Original Public Record Copy (1900).

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2 years ago

Subtract. – 0.41 – 8.91<br> a. –9.32<br> b. –8.50<br> c. 8.50<br> d. 9.32

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3 years ago

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above <em>18 values for n are possible.</em>

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3 years ago

How to solve this problem

guapka [62]

2193 x 10(little 37) over 79

or

≈2.77595 x 10(little 38)

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3 years ago

Find the area for the circle below<br>A. 61.42<br>B. 36.25<br>C. 78.54<br>D. 108.85

Lorico [155]

C
Source: trust me bro

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