Answer:
3.659 is the answer
Step-by-step explanation:
Given:
The inequality is

To find:
The value of x and then graph on the number line.
Solution:
We have,

Subtracting 19 from both sides, we get


It means all the real values of x which are less than or equal to 4 are in the solution set. So, an arrow approaches towards left from x=4 as shown in the below figure.
Answer:
Not a function
Step-by-step explanation:
This is not a function because there are different outputs for the same input.
Answer:
a) P=0.3174
b) P=0.4232
c) P=0.2594
d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.
Step-by-step explanation:
The appropiate distribution to model this is the hypergeometric distribution:

a) What is the probability that none of the questions are essay?

b) What is the probability that at least one is essay?

c) What is the probability that two or more are essay?
