Gland cells are most likely to possess a large number of Golgi bodies.
Please mark my answer as the brainliest answer, I'd really appreciate it, thanks!
Two traits that we are examining are the color (purple/white) and the smoothness.
In our sample, we have 135 individuals ( 75 +28+24+8= 135).
Since we know that expected ratio of a dihybrid cross, is <span>9:3:3:1 we can calculate what is the expected values of each phenotype is.
So, for the white wrinkled phenotype, we expect that there will be one-sixteenth of the whole sample ( there are 16 parts of the whole sample 9+3+3+1=16).
So, we multiply the whole sample- 135 with one-sixteenth (or </span>0.0625) and get 8,4375.
When you calculate the values for all phenotypes you get results shown in the attached excel table.
When you have your expected and experimental values you compare them with a chi-square test. (The test determines if the difference between the expected and experimental results is statistically significant).
Answer:
You could generate cDNA libraries and compare the transcribed regions of the genome
I'm gonna say false because it is one cell in a multicellular meaning different parts have different functions
The process that is directly responsible for the formation of the bud on the hydra is;
B - Mitosis