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ivolga24 [154]
3 years ago
5

The Punnett square is for a test cross of two mice that were purebred for two different traits. What will their offspring be? Fi

ll in the white boxes of the Punnett square with all possible offspring genotypes

Biology
1 answer:
Eva8 [605]3 years ago
7 0

Answer: All their offsprings will be heterozygous for both traits.

Explanation: The offsprings of this cross will be heterozygous for the two traits. Each the offspring will have one dominant allele and one recessive allele for both traits. All the offsprings will have a genotype of BbEe. B is a dominant allele and b is a recessive allele while E is a dominant allele and b is a recessive allele.

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When fruit fly embryos first begin to develop, a large cell is generated that contains over 8000 nuclei that are genetically ide
aniked [119]

Answer:

The embryo passes through multiple rounds of the cell cycle, but cytokinesis does not occur during M phases.

Explanation:

The cell cycle includes a series of events that make new cells from the existing cells. During the process, nuclear division during the M phase produces daughter nuclei. Nuclear division is followed by cytokinesis. Cytokinesis is the division of cytoplasm and results in the formation of daughter cells.

If a cell undergoing cell cycle forms daughter nuclei by mitosis, all the daughter nuclei are genetically identical. In the absence of cytokinesis, cytoplasm would not divide and the daughter nuclei will remain in the parent cell only. Repeated nuclear division without cytokinesis would produce multiple nuclei present in the parent cell.

3 0
3 years ago
1. At the time this video was filmed (2007), what was Gallo's estimate of the percentage of earth's oceans that had been investi
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Answer:

about 5% of the ocean had been explored as of this video being filmed in 2007.

Explanation:

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7 0
2 years ago
Before a captive breeding program and subsequent reintroduction of the black-footed ferret it is believed that their total popul
irga5000 [103]

Answer:

a) 99.93%

b) 99.98%

Explanation:

Given that:

Total population size was only around 18 individuals ( for  black-footed ferret)

If the annual survival rate in the wild was 0.4%.

a)

What is the probability that all 18 would have died in a single year?

To find that; we multiply the annual survival rate in the wild with the total population; which is:

(0.4%×18) = 0.072%

Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.

= (100.00% - 0.072%)

= 99.93%

b)

What is the probability that all 18 would have died in a single year if canine distemper was present?

Given that;

Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.

To determine the probability; we have:

1 - Annual mortality rate = annual survival rate

1 - 0.89 = 0.11 %

Therefore, 0.11% of 18 individuals = (0.0011 × 18)

= 0.0198%

Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate

= (100 - 0.0198)%

= 99.98%

7 0
3 years ago
1. Single called organisms are part of the ____ group
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Answer:

i think it is A but  lmk if it is wrong

Explanation:

8 0
3 years ago
Which characteristic of living things would apply to adapting to light and temperature variation?
skad [1K]

Answer:

Responsiveness to the environment/adaptation. This is one of the 8 characteristics of living things.

Explanation:

5 0
3 years ago
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