Okay, so for example, A. A which equals 0.75 can be put in between 0 and 1 but closer to 1 by a little bit. They are just asking you to graph it, thats all.
3t+9≥15 => 3t ≥ 6 => t ≥2 => t= [2,∞)
Hope that helps, have a nice day!! ^^
Answer:
1350m
Step-by-step explanation:
Let the distance ran by Denise, Farah and Elaine be D, F and E meters respectively.
From the given information,
D= ⅔(E +F) -----(1)
E= ½(D +F) -----(2)
Let's get rid of the fraction so the equations are much easier to work with.
From (1):
3D= 2(E +F) <em>(Multiply both sides by 3)</em>
3D= 2E +2F -----(3) <em>(</em><em>Expand</em><em>)</em>
From (2):
2E= D +F -----(4)
Substitute (4) into (3):
3D= D +F +2F
3D -D= 3F
2D= 3F
Given that Farah ran 360m, F= 360.
2D= 3(360)
2D= 1080
D= 1080 ÷2
D= 540
2E= D +F
2E= 540 +360
2E= 900
E= 900 ÷2
E= 450
Total distance the 3 girls ran
= D +F +E
= 540 +360 +450
= 1350m
Alternatively, you could start by substituting F= 360 to equations (1) and (2).
Answer:
0.1894 = 18.94% probability that there will be fewer than 69 broken pretzels in a run.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A pretzel company calculated that there is a mean of 73.5 broken pretzels in each production run with a standard deviation of 5.1.
This means that 
Find the probability that there will be fewer than 69 broken pretzels in a run.
This is the p-value of Z when X = 69.



has a p-value of 0.1894
0.1894 = 18.94% probability that there will be fewer than 69 broken pretzels in a run.
So one hour is 60 minutes,
5/6 of an hour would be, 50 minutes. Basically 60/6=10 and 10*5=50
so if the robot does 8 tasks in 50 minutes and each tasks takes the same amount, the equation would be 50/8
50/8= 6.25
Each task is 6 minutes and 25 seconds.