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ale4655 [162]
3 years ago
6

A container at a paper clip factory holds 2.1*10^3 pounds of paper clips. There are 9.6*10^5 paper clips in the container. Find

the approximate weight of each paper clip in ounces. (1 pound= 16 ounces)
Show Your Work.
Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0
Divide the total weight (2.1 * 10^3 lbs.) by the total quantity of things (9.6 * 10^5) to get the lbs./paperclip. 

Then, multiply that number by 16 to get ounces/paperclip.
Mnenie [13.5K]3 years ago
3 0

Answer:

The approximate weight of each paper clip is 0.035 ounce.

Step-by-step explanation:

A container at a paper clip factory holds 2.1*10^3 pounds of paper clips.

= 2.1\times1000=2100 pounds

There are 9.6*10^5 paper clips in the container.

= 9.6\times100000=960000

Now we get that 960000 paper clips weigh 2100 pounds.

So, each paper clip will weigh = \frac{2100}{960000} = 0.0021875 pounds

And 1 pound = 16 ounces

0.0021875 pounds = 16\times0.0021875 = 0.035 ounce

Hence, the approximate weight of each paper clip is 0.035 ounce.

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Answer: 8 books/ hour

Explanation:

240 / 30 = 8 books/ hour

I hope this helped!

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7 0
3 years ago
Read 2 more answers
Pleae help me i will mark you brainliestttttttttt
muminat

Answer:

The last one.

Step-by-step explanation:

7 0
3 years ago
512, 256, 128, 64, __, __, __, ...​
Cerrena [4.2K]

The complete pattern is: 512, 256, 128, 64, 32, 16, 8, ( and extended ) 4, 2, 1!

I do this pattern in my head literally all the time!

4 0
3 years ago
For each of the following binomial random variables, specify n and p. (a) A fair die is rolled 50 times. X = number of times a 5
Keith_Richards [23]

Answer:

a) n = 50, p = \frac{1}{6}

b) n = 16, p = \frac{1}{100}

c) n = 26, p = 0.25, \mu = 6.5

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

(a) A fair die is rolled 50 times. X = number of times a 5 is rolled

The die is rolled 50 times, so n = 50.

Each roll can have 6 outcomes. So the probability that 5 is rolled is p = \frac{1}{6}

(b) A company puts a game card in each box of cereal and 1/100 of them are winners. You buy sixteen boxes of cereal, and X = number of times you win.

You buy 16 boxes of cereal, so n = 16.

1 of 100 are winners. So p = \frac{1}{100}.

(c) Jack likes to play computer solitaire and wins about 25% of the time. X = number of games he wins out of his next 26 games.

He plays 26 games, so n = 26.

He wins 25% of the time, so p = 0.25

We have that \mu = np. So \mu = 26*0.25 = 6.5

6 0
4 years ago
16 POINTS HELP ASAP plzzzzzzzzz
schepotkina [342]

Answer:

                            \large\boxed{\large\boxed{\sqrt{3}

Explanation:

You are comparing irrational numbers.

By inspection, i.e. at first sight you can only compare \sqrt{3} \text{ }and\text{ } 2\sqrt{3} because they have the same radicand.

You can order: \sqrt{3}

You can introduce the 2 inside the radical by squaring it:

       2\sqrt{3}=\sqrt{2^2\times3}=\sqrt{12}

Since 5 is between 3 and 12, you can order:

  • \sqrt{3}

Which is:

  • \sqrt{3}

You must know that π ≈ 3.14.

5 is less than 9 and the square root of 9 is 3; hence, \sqrt{5} and \sqrt{5}

Now you must determine whether π is less than or greater than \sqrt{12}

Using a calculator or probing numbers between 3 and 4 you get \sqrt{12} \approx3.46

Hence, the complete order is:

  •            \sqrt{3}
5 0
4 years ago
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