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Taya2010 [7]
3 years ago
12

Which simplifications of the powers of i are correct? There may be more than one correct answer.

Mathematics
1 answer:
fredd [130]3 years ago
6 0

\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark

\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes

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I need help with this question please
Elza [17]

The changes in Z would be = 6.1× 10^-4.

<h3>Calculation of the unknown value</h3>

Z = Sin (x³ +y³)

Where X = 0.3

y = 0.2

Z= Sin ( 0.3³ + 0.2³)

Z= Sin ( 0.027 + 0.008)

Z= Sin ( 0.035)

Z= 6.1× 10^-4

Therefore, the changes in Z would be = 6.1× 10^-4.

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brainly.com/question/10873737

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