3 years ago

Pls help ASAP I need it in 10 mins

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer:

I could only figure out that the range is the 2nd to last one. Sorry. Hope you get it right!

Step-by-step explanation:

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-3(z-8)+10=-5<br> What is z equal to?

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Step-by-step explanation:

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Factor the expressions .<br> 36 + 8z

Sophie [7]

Answer:

4 × ( 9 + 2z)

Step-by-step explanation:

36 + 8z = 4 × (9) + 4 × (2z) ; so here 4 is a common factor

= 4 × ( 9 + 2z)

we can also write it like this

36 + 8z = 2 × ( 18 + 4z)

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3 years ago

A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2, drawn from the 11, will

svet-max [94.6K]

The required probability is $\frac{36}{55}$

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, $\text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Probability for first draw to be non-defective $=\frac{11-2}{11}=\frac{9}{11}$

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective $=\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}$

(printers after first slot = 10; total defective printers = 2)

Then, total probability $=\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}$

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