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3 years ago

Which statement describes the domain of the function f (x) = StartFraction 3 x Over 4 x squared minus 4 EndFraction?

Mathematics

2 answers:

Lelechka [254]3 years ago

7 0

Answer: D on edge, all real numbers except x = –1 and x =

Step-by-step explanation:I took the test and its right.

drek231 [11]3 years ago

6 0

<em>The domain is the set of all real number except 1 and -1</em>

<h2>Explanation:</h2>

We have the following function:

$f(x)=\frac{3x}{4x^2-4}$

So the domain is the set of all x-values for which the function is defined. Since we have $4x^2-4$ in the denominator, then:

$4x^2-4\neq 0 \\ \\ \\ Factor \ out \ 4: \\ \\ 4(x^2-1)\neq 0 \\ \\ (x^2-1)\neq 0 \\ \\ \\ Difference \ of \ squares: \\ \\ (x-1)(x+1)\neq 0 \\ \\ \\ So: \\ \\ \\\boxed{x\neq 1 \ and \ x\neq -1}$

In conclusion:

<em>The domain is the set of all real number except 1 and -1</em>

<h2>Learn more:</h2>

Domain: brainly.com/question/13691720

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When 63x3y 105x2y is divided by -7xy, the quotient is . if this quotient is divided by , the result is 3x 5.?

solong [7]

-9x^2-15x. Each one is divided by -7xy

7 0

3 years ago

a normal distribution has a mean of 56 and a standard deviation of 8. Find the percentage of data values that are in the given i

vekshin1

Answer:

12) Between 40 and 64 = 0.815

13) Between 32 and 40 = 0.0235

14) Between 56 and 64 = 0.34

15) At most 56 = 0.515

16) At least 72 = 0.025

17) At most 64 = 0.855

Explanation:

To answer this, we will convert each of the values into their standardized form to make this easier.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ

x = Each value

μ = Mean = 56

σ = Standard deviation = 8

12) Between 40 and 64

For 40,

z = (x - μ)/σ = (40 - 56)/8 = (-16/8) = -2

For 64

z = (x - μ)/σ = (64 - 56)/8 = (8/8) = 1

So,

Between 40 and 64 = Between -2 and 1

From the curve, noting that the central point is the mean, with standard score of 0, the lines before it move in step of 1 standard deviation towards the negative side, that is, -1, -2, etc. And the lines before the central point move towards the positive side, that is, 1, 2, 3, etc.

So,

Between -2 and 1 = 0.135 + 0.34 + 0.34 = 0.815

13) Between 32 and 40

For 32,

z = (x - μ)/σ = (32 - 56)/8 = (-24/8) = -3

For 40,

z = (x - μ)/σ = (40 - 56)/8 = (-16/8) = -2

So,

Between 32 and 40 = Between -3 and -2 = 0.0235

14) Between 56 and 64

For 56,

z = (x - μ)/σ = (56 - 56)/8 = (0/8) = 0

For 64,

z = (x - μ)/σ = (64 - 56)/8 = (8/8) = 1

Between 56 and 64 = Between 0 and 1 = 0.34

15) At most 56

For 56,

z = (x - μ)/σ = (56 - 56)/8 = (0/8) = 0

At most 56 = At most 0 = 0.0015 + 0.0235 + 0.15 + 0.34 = 0.515

All the regions before z = 0)

16) At least 72

For 72,

z = (x - μ)/σ = (72 - 56)/8 = (16/8) = 2

At least 72 = At least 2 = 0.0235 + 0.0015 = 0.025

(All the regions from z = 2 to the end)

17) At most 64

For 64,

z = (x - μ)/σ = (64 - 56)/8 = (8/8) = 1

At most 64 = At most 1 = 0.0015 + 0.0235 + 0.15 + 0.34 + 0.34 = 0.855

(All the regions before z = 1)

Hope this Helps!!!

4 0

3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

harkovskaia [24]

Answer:

○ $\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]$

Step-by-step explanation:

You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of $\displaystyle -\frac{\sqrt{3}}{2},$ which gives you $\displaystyle -\frac{2\sqrt{3}}{3}.$