The zeros of given function 
is – 5 and – 3
<u>Solution:</u>
We have to find the zeros of the function by rewriting the function in intercept form.
By using intercept form, we can put value of y as to obtain zeros of function
We know that, intercept form of above equation is 
Taking “x” as common from first two terms and “3” as common from last two terms
x (x + 5) + 3(x + 5) = 0
(x + 5)(x + 3) = 0
Equating to 0 we get,
x + 5 = 0 or x + 3 = 0
x = - 5 or – 3
Hence, the zeroes of the given function are – 5 and – 3
We look for the minimum of each function.
For f (x) = 3x2 + 12x + 16:
We derive the function:
f '(x) = 6x + 12
We match zero:
6x + 12 = 0
We clear the value of x:
x = -12/6
x = -2
We substitute the value of x in the equation:
f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
f (-2) = 4
For g (x) = 2sin(x-pi):
From the graph we observe that the minimum value of the function is:
y = -2
Answer:
A function that has the smallest minimum y-value is:
y = -2
Answer:
2 students
Step-by-step explanation:
First, you find the number of students eating either salads and sandwiches. Then, you add the number of students eating salads and sandwiches together. Finally, you will subtract that number from the 12 total students
<h3>2/3 * 12/1 = 8 (sandwiches)</h3><h3>1/6 * 12/1 = 2 (salads)</h3><h3>8 + 2 = 10 (combined)</h3><h3>12 - 10 = 2 students</h3><h3 />
Answer:
in my opinon, this table is proportional
The answer is because 3 squared =9
