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3 years ago

A shape is shown on the graph

Mathematics

1 answer:

Leviafan [203]3 years ago

7 0

I believe it’s 90 I’m not sure but

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Which of the following options have the same value as 30% percent of 81?

Shkiper50 [21]

Answer:

24.3

Step-by-step explanation:

30% of 81 can be found by converting the percentage into the fraction 0.30 and then multiplying: 0.30(81) = 24.3

5 0

2 years ago

Which is an exponential decay function? f(x) = 0.2(5/3)^x f(x)=-3.1^x f(x)=10^x f(x)=-2(0.7)^x

Serjik [45]

-2(.7)^x is the only function where decay would be demonstrated of these

4 0

2 years ago

Read 2 more answers

The vegetable garden has 95 ripe plants. The number of tomatoes is 16 fewer than twice the number of squashes. How many of each

RideAnS [48]

Answer:

Tomatoes = 39.5

Squash = 55.5

Step-by-step explanation:

T (tomatoes) = S - 16

S + T = 95

we plug it in now

S + (S - 16) = 95

2s = 95 + 16

2s = 111

s = 55.5??

hm. Let's go with it

T = 55.5 - 16

T = 39.5

39.5 + 55.5 = 95

I...guess?

5 0

2 years ago

Jack's pancake recipe calls for 2 tsp baking powder and 3 c of flour.

expeople1 [14]

Answer: 6 tsp of baking powder.

Explanation: 1 pancake= 2 tsp of baking powder and 3c of flour. If there is 9c of flour you would assume that is 3 pancakes meaning 2 tsp times 3 is 6 tsp of baking powder. PLEASE MAKE ME THE BRAINLIEST.

3 0

2 years ago

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago