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coldgirl [10]
3 years ago
11

A shape is shown on the graph

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0
I believe it’s 90 I’m not sure but
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The owner of a retail store is tracking his inventory for an annual report. The graph shows the remaining inventory for a partic
aliina [53]
Y = -2.8x +69.4

Let y represent units of inventory, and x represent days since the last replenishment. We are given points (x, y) = (3, 61) and (13, 33). The line through these points can be described using the 2-point form of the equation of a line:
... y -y1 = (y2-y1)/(x2 -x1)(x -x1)
Filling in the given point values, we have ...
... y -61 = (33 -61)/(13 -3)(x -3)
Simplifying and adding 61, we get ...
... y = -2.8x +69.4
5 0
2 years ago
Five more than a number tripled is half the number. What is the number?
Alina [70]
The equation:
let x represent the unknown number
5+y3=x*05 (or x divided by 2)
y represents the tripled number and x represents the end result. Hope this helps!
8 0
3 years ago
Read 2 more answers
Why is it helpful to represent fractions and division with models? (pls make answer pretty long, thanks :)
eimsori [14]

Answer:

Whether you're teaching the meaning of fractions or fraction operations, visual models can help students connect fractions to what they already know. Division is an essential foundation for fractions. Once students can divide objects into equal groups, they can begin to grasp dividing a whole into equal parts.

Step-by-step explanation:

6 0
2 years ago
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You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which
stellarik [79]
To model this situation, we are going to use the compound interest formula: A=P(1+ \frac{r}{n} )^{nt}
where
A is the final amount after t years 
P is the initial deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
t is the time in years 

For account A: 
We know for our problem that P=2000 and r= \frac{2.25}{100} =0.0225. Since the interest is compounded monthly, it is compounded 12 times per year; therefore, n=12. Lets replace those values in our formula:
A=2000(1+ \frac{0.0225}{12} )^{12t}

For account B:
P=2000, r= \frac{3}{100} =0.03, n=12. Lest replace those values in our formula:
A=2000(1+ \frac{0.03}{12} )^{12t}

Since we want to find the time, t, <span>when  the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span>2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000

Now that we have our equation, we just need to solve for t:
2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000
(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}
(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}&#10;{2}
ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})
12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})
t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})
t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}
17.47

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>
5 0
3 years ago
If you drive 130 miles and it takes you Two hours and six minutes and then you drive back on the same route but it takes you two
Vilka [71]
You can gain it by taking an hr and thirty min trip and on the way back takes hr and forty five min. That is how you gain your precious time back!!!✍️☃️⚽️
4 0
3 years ago
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