The student did not make the opening of each arc drawn from S and T greater than half the length of the line ST. When drawing a perpendicular bisector, the arcs should go past the center of the line segment.
Given:
The piecewise rectangular figure.
To find:
The area of the piecewise rectangular figure.
Solution:
Draw a line and divide the given figure in two parts (a) and (b) as shown in the below figure.
Figure (a) is a rectangle of length 5 yd and width 3 yd. So, the area of the rectangle is:
Figure (b) is a square of edge 2 yd. So, the area of the square is:
The area of the given figure is:
Therefore, the area of the given figure is 19 square yd.
<span>GIVEN:
∠D congruent to ∠T
∠E congruent to ∠U
DE congruent to UT
answer
</span><span>ASA Postulate</span>
Answer:
since 7 is raised to the power 0 the answer is
a) linear polynomial with zero terms
Answer:
1872 cm^3
Step-by-step explanation:
To solve this you can split the shape into two parts, the large rectangle with length 18 and width 8, and the small rectangle with length 6 and width 3.
So now apply the volume formula,
for the larger shape,
V = Area * height
V = L*W *H
V = 18*8*12
The volume of one part is 1728.
Now for the second shape on top,
V = L*W*H
V = 6*8*3 = 144
Now add the two, 1728+ 144 = 1872
1872 cubic centimeters
