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Degger [83]
3 years ago
14

What is the solution to the system of equations?

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

A: There is no solution

Step-by-step explanation:

This is not a very likable question.

Y=3x-4

9x-3y=14

Put the y value from the first equation into the second.

9x - 3(3x - 4) = 14               Remove the brackets

9x - 9x + 12 = 14               Combine like terms on the left

12 = 14                                 When you get this kind of conclusion, that means there is no solution. I'll graph these two for you.

Blue: y =3x - 4

Green: 9x - 3y = 14

They never touch they never meet: they are parallel. They don't give a solution.

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Solve the simultaneous equations:<br><br> 5x + 3y = 9<br> 7x - 2y = 25<br><br> x=__<br> y=__
kondor19780726 [428]

Answer:

x= 3, y= -2

Step-by-step explanation:

5x+3y= 9

x= 25÷7 + 2÷7 y

5(25÷7 +2÷7 y)

5( 25÷7 +2÷7 y ) + 3y= 9

y= -2

x= 25÷7 + 2÷7 x (-2)

x= 3

5 0
2 years ago
Can someone please help me out with this question ??
Nezavi [6.7K]

Answer:

A = 28 units ^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

The base is 14 and the height is 4

A = 1/2 (4) * 14

A = 28 units ^2

5 0
2 years ago
Read 2 more answers
Ƒ(x) = x − 9 if the domain is (3, -3, 0)
amid [387]

Answer:

f(3) = -6

f(-3) = -12

f(0) = -9

Step-by-step explanation:

Substitute each number for x.

f(3) = 3 - 9 = -6

f(-3) = -3 - 9 = -12

f(0 ) = 0 - 9 = -9

4 0
2 years ago
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Hank’s pickup can travel 60 miles on 5 gallons of gas. How many gallons will Hank’s pickup need to travel 36 miles
Scorpion4ik [409]

60 / 5 = 12 miles per gallon


36 miles = 12 miles / gal *  x gallons

divide  by 12

36/12 =x gallons

3  =x

He needs 3 gallons


7 0
3 years ago
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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

7 0
2 years ago
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