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marta [7]
3 years ago
10

HELPPPP PLEASE WITH THIS QUESTION

Mathematics
2 answers:
Brut [27]3 years ago
6 0
So, this question is like finding the radius given the circumference.
Circumference is 113, and the formula to find the radius is r = C/2 \pi
r = 113/2 \pi

R ≈ 17.98
So, the most likely length of of the blade would be B) 18 inches.
Liono4ka [1.6K]3 years ago
6 0
It should be about 18 inches
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Answer:

17 is a required answer.

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The area of a square is 102 square units. What is an
Neko [114]

Answer:

Between 10 and 11.

Step-by-step explanation:

To begin, we can look at the problem as such. If we take the first answer choice, we can find the squares of both numbers giving us: (Remember that the area of a square is A=L²)

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3 years ago
Read 2 more answers
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natta225 [31]
Check the picture below.

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ -2}}\quad ,&{{ 5}})\quad &#10;%   (c,d)&#10;&({{ -1}}\quad ,&{{ 1}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-5}{-1-(-2)}\implies \cfrac{1-5}{-1+2}&#10;\\\\\\&#10;\cfrac{-4}{1}\impliedby\stackrel{slope~of}{PQ}

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ -1}}\quad ,&{{ 1}})\quad &#10;%   (c,d)&#10;&({{ 7}}\quad ,&{{ 3}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{3-1}{7-(-1)}\implies \cfrac{3-1}{7+1}&#10;\\\\\\&#10;\cfrac{2}{8}\implies \cfrac{1}{4}\impliedby \stackrel{slope~of}{QR}

now, two lines who meet at a perpendicular angle, have a negative reciprocal slope of each other, to make it short, if you multiply their slopes, you should get -1 as the product, if they're indeed perpendicular.

\bf \stackrel{PQ}{-\cfrac{4}{1}}\cdot \stackrel{QR}{\cfrac{1}{4}}\implies -1

low and behold, they're indeed perpendicular, thus that angle is indeed a right-angle.

3 0
3 years ago
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poizon [28]

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6 0
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7 0
3 years ago
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