Can you post your middle school questions in the middle school area...
9 4/5 - 2 3/10 = X
9 8/10 - 2 3/10 = X
7 5/10 = X
7 1/2 is simplest form
Answer:
7776
Step-by-step explanation:
Yes.
Answer:
Option A) angle bisector
Step-by-step explanation:
Angle Bisector:
- An angle bisector is a line that divides an angle into two equal parts.
- The angle bisector divide the angle in two equal parts.
- An angle bisector is equidistant from the sides of the angle when measured along a segment perpendicular to the sides of the angle.
- It cuts the angle into half.
- Thus, a sector can be divided into two equal sectors by drawing an angle bisector.
To divide the sector into two congruent sectors we can use the angle bisector construction.
Thus, the correct answer is
Option A) angle bisector
Answer:
15.74% of women are between 65.5 inches and 68.5 inches.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What percentage of women are between 65.5 inches and 68.5 inches?
This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.
X = 68.5



has a pvalue of 0.9987
X = 65.5



has a pvalue of 0.8413
So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.