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Kamila [148]
3 years ago
6

Two consecutive even integers have a sum of 74. What are the integers?

Mathematics
2 answers:
goblinko [34]3 years ago
7 0

Answer:

<h2>36 and 38</h2>

Step-by-step explanation:

n,\ n+2-\text{two consecutive even integers}\\\\\text{The equation:}\\\\n+(n+2)=74\\\\n+n+2=74\qquad\text{subtract 2 from both sides}\\\\2n=72\qquad\text{divide both sides by 2}\\\\n=36\\\\n+2=36+2=38

Mazyrski [523]3 years ago
7 0

Answer:

36 and 38

Step-by-step explanation:

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If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure &amp; the perimeter of triangle ABC.
harina [27]

Answer:

Perimeter = 38.6

Step-by-step explanation:

Given

A\ B = 13

B\ F = 9

F\ C = 5.6

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

Perimeter = A B + B\ C + A\ C

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

B\ C^2 = B\ F^2 + F\ C^2

Substitute values for BF and FC;

B\ C^2 = 9^2 + 5.6^2

B\ C^2 = 81 + 31.36

B\ C^2 = 112.36

B\ C^2= \sqrt{112.36

B\ C = 10.6

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

A\ B^2 = B\ F^2 + A\ F^2

Substitute values for B F and A B;

13^2 = 9^2 + A\ F^2

169= 81 + A\ F^2

A\ F^2 = 169 - 81

A\ F^2 = 88

A\ F = \sqrt{88

A\ F = 9.4

Since F lies on line A C:

A\ C = A\ F + F\ C

A\ C = 9.4 + 5.6

A\ C = 15.0

Recall that:

Perimeter = A\ B + B\ C + A\ C

Perimeter = 13 + 10.6 + 15.0

Perimeter = 38.6

<em>Hence, the perimeter is 38.6</em>

3 0
3 years ago
joe is making punch for the class party he makes 3 gallons how much punch does joe make select all the correct possible answers
aalyn [17]

Answer:

3 gallons.... It says it in the question

Step-by-step explanation:

3 0
3 years ago
∠A and ∠B are vertical angles. If ∠A=8x+14 and ∠B=2x+50, what is m∠B?
Maslowich

Answer:

∠B = 62°

Step-by-step explanation:

Because ∠A and ∠B are vertical angles they are equal hence we can write

∠A = ∠B

8x + 14 = 2x + 50

Now we have to solve for x

To do so, subtract 2x on both sides of the equation:

6x + 14 = 50

Now, subtract 14 on both sides of the equation

6x = 36

Now, divide 6 on both sides of the equation

x = 6

To find m∠B you have to you have to plug in x = 6 back into the ∠B equation

∠B = 2(6) + 50

∠B = 62°

4 0
3 years ago
How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?
Alla [95]

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

  • If k is any positive real number, then the graph of f(x) - k is  the graph of y = f(x) shifted downward k units.
  • If p is a positive real  number, then the  graph of f(x+p) is  the graph of y=f(x)  shifted to the left  p units.

The function y = \sec(x+3)-7 comes from the base function y= sec(x).  

Since 3 is added added on the inside, this  is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift  down 7 units.

Therefore, the transformation on the given function is shifted  3 units left and 7 units down


3 0
3 years ago
Read 2 more answers
A pilot is flying a CRJ-900 from Phoenix, Arizona, to Louisville, Kentucky. The aircraft cannot take off or land if the temperat
ioda

We need to find an inequality that represents the possible landing or take of conditions of an aircraft, the required graph and one case where the inequality will be tested.

The required inequality is -40.

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The pilot could not have taken off on June 1990, the temperature in Phoenix, Arizona.

Let the temperature be denoted by x

The temperature cannot be at or below -40^{\circ}\text{F}, so

x>-40

The temperature cannot be at or above 118^{\circ}\text{F}, so

x

The inequality will be -40.

In the graph it can be seen that all points between -40 and 118 falls in the shaded region but it will exclude the points -40 and 118.

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The temperature in June 1990 in Phoenix, Arizona was 122^{\circ} which is more than 118^{\circ}\text{F}.

Hence, the pilot could not have taken off on this day.

Learn more:

brainly.com/question/20383699

brainly.com/question/11612965

4 0
2 years ago
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