<span>The expression
represents the total number of stamps that they will have if t represents the
number of stamps Tim </span>
Can be solve by adding the stamps of tim and Hannah
Let x be the total stamps of tim and Hannah
X = 60 + t
<span> y-4=-8(x-1) is linear
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</span><span>y=x4 is non linear, it is a parabola or a curved line
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</span><span>y-x2=4.5 is non linear as it is curved
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</span><span>3x + 5y = 15 is linear</span>
X/8+12=16
Subtract 12 to both side
x/8+12-12=16-12
x/8=4
Multiply each side by 8
(x/8)8=4(8)
x=32
Check:
Substitute x with 32
32/8+12=16
4+12=16
16=16. As a result, x equal 32. Hope it help!
Answer:
16 1/12
Step-by-step explanation:
The LCD of 6 1/3 + 5 1/2 + 4 1/4 is 12; 12 is evenly divisible by 3, 2 and 4.
We can rewrite this expression as:
6 + 5 + 4 + 1/3 + 1/2 + 1/4, or
15 +4/12 + 6/12 + 3/12, or
15 + 13/12, or
16 1/12
To answer we let x be the amount of money that Sam invested during the first year.
Below are the expressions translated from the given word forms for the amount invested.
Sam:
2nd year : amount = 5x/2 - 2000
3rd year : amount = x/5 + 1000
The sum of money invested by Sam is:
x + (5x/2 - 2000) + (x/5 + 1000)
Similarly, we derive the expressions that we use for the amount that Sally invested.
Sally
1st year : amount = 3x/2 - 1000
2nd year : amount = 2x - 1500
3rd year : amount = x/4 + 1400
The total amount that Sally invested is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Equating the two equations:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Solving for x,
x = 2000
For Sally's investment in the third year:
amount = x/4 + 1400 = (2000/4 + 1400) = 1900
ANSWERS:
Sam's first year = $2000
Sally's third year = $1900
