Answer:
<h2>Perimeter = 42m</h2><h2>length of the diagonal ≈ 16m</h2>
Step-by-step explanation:
The Area of the rectangular field is expressed as A = LB and its perimeter
P = 2(L+B)
L is the length of the rectangular field
B is the Breadth of the rectangular field
If the length of a rectangular field is twice its breadth i.e L = 2B and the area is 98m² then;
98 = LB
98 = 2B*B
98 = 2B²
B² = 98/2
B² = 49
B = √49
B = 7m
if B = 7m
L = 98/B
L = 98/7 = 14m
The perimeter of the field P = 2(L+B)
P = 2(14+7)
P = 2*21
P = 42m
The perimeter of the field is 42m.
The length of the diagonal of the field can be expressed using Pythagoras theorem.
d = √L²+B²
d = √14²+7²
d = √196+49
d = √245
d = 15.7m ≈ 16m
Hence, the approximate length of the diagonal of the field is 16m
