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alex41 [277]
3 years ago
13

Mean, medium, & mode of 17, 6, 20, 11, 13, 20, 18

Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Step-by-step explanation:

medium -11

I don't know about mean & mode

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The square root of a2+1=2
user100 [1]
Remove the radical by raising each side to the index of the radical. a = √ 3 , − √ 3 a=3,-3 a ≈ 1.73205080 , − 1.73205080
7 0
4 years ago
What is the value of x? Enter your answer in the box.
Radda [10]

Answer:

x = 8

y = 6

Step-by-step explanation:

First and foremost, it's an equilateral triangle, therefore all sides and angles are equal.

Knowing that the sum of angle in a triangle is 180°, therefore each angle is 60°.

Then equating (7x+4)° to 60, we have that,

7x+4=60

7x=60-4

7x=56

x=56÷7

x=8.

5 0
2 years ago
Find the slope of the line in the image.<br> someone plz helpppp
pogonyaev

Answer:  The answer I got is -2/4 Hope this help :)

Step-by-step explanation:(-2,6)(2,4)

M=y2-y1

   x2-x1

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2-(-2)   =  4

The slope is -2/4

4 0
3 years ago
Read 2 more answers
If a=mg-kv2/m,find,correct to the nearest whole number the value of v when a=2.8,m=12,g=9.8 and k=8/3
Cerrena [4.2K]

Answer:

v = 23

Step-by-step explanation:

Formatting the question gives;

a = mg - kv² / m

Make v subject of the formula as follows;

(i) Multiply both sides by m

ma = m²g - kv²

(ii) Collect like terms

kv² = m²g - ma

(iii) Divide through by k

v² = (m²g - ma) / k

(iv) Take the square root of both sides

v = √ [(m²g - ma) / k]            --------------(ii)

From the question:

a = 2.8

m = 12

g = 9.8

k = 8/3

Substitute these values into equation (i) as follows;

v = √ [(12²(9.8) - 12(2.8)) / (8/3)]

v = √ [(1411.2 - 33.6) / (8/3)]

v = √ [1377.6 / (8/3)]

v = √ [1377.6 x (3/8)]

v = √ [1377.6 x 3 / 8)]

v = √ [516.6]

v = 22.73

v = 23 [to the nearest whole number]

Therefore v = 23 to the nearest whole number    

3 0
4 years ago
The constant ratio between of consecutive terms in a geometric sequence is called the
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Answer:

Its called the common ratio.

Hope this helps!

8 0
3 years ago
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