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viva [34]
4 years ago
11

Plz answer quick!!!

Mathematics
1 answer:
erica [24]4 years ago
4 0

75.36 is the answer.

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HELLLOPPPPPPP HELPPP ASAPPP PLEASE !!
bonufazy [111]

Answer:

10 = c

Step-by-step explanation:

Distribute -4 to the parentheses:

8 = 8c - 4(c + 8)

8 = 8c - 4c - 32

Add like terms:

8 = 4c - 32

Add 32 to both sides:

40 = 4c

10 = c

8 0
4 years ago
Read 2 more answers
15. B(-2, -9), C(0,-5), D(6,-3), E(4, -7)
artcher [175]

Answer:

BC= 2√5

CD= 2√10

DE= 2√5

BE= 2√10

slope of BC = 2

slope of CD = 1/3

slope of DE = 2

slope of BE = 1/3

Step-by-step explanation:

formula for distance = √(x2-x1)²+(y2-y1)²

formula for slope = (y2-y1)/(x2-x1)

5 0
3 years ago
Helpppppppppppppppppppppppppppppppppppppppppp
solong [7]

Answer:

Please check explanations for answer

Step-by-step explanation:

Here, we want to check the given list and state the true values;

1. This is true

Compound interest has the exponent nt; simple interest has no exponent

2. This is false

Simple interest is only earned on the principal which is the amount deposited

3. True

Due to its multiplication chain, it earns more money as we can compound more than once within the given time frame

4. This is false; check explanations above

5. This is true

Its value is only based on the amount invested originally

6. This is false

simple interest earns the same amount annually based on rate

7. This is false

Both considers the time factor t in their formulas

8. This is true

The interest and principal forms the principal for another compounding time

5 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
Anyone ??<br> I’m confused
Ad libitum [116K]
+2+(-3)+(-1)+4(-5)+(-3) ok so first 2 is positive and 3 is negative there both different signs so u subtract +2+(-3)=-1+(-1)=0+4=4+(-5)=-1+(-3)=-4 your answer is 4
4 0
3 years ago
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