Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
I think its (1,1)please correct me if i am wrong. have a good day!! :)
Answer:f(x) is 6)×-3
Step-by-step explanation:i think i it will help
Step-by-step explanation:
x + 53 = 90
x = 37
answer is 37
Answer:
X = 30
Step-by-step explanation:
Because every triangle adds to the total of 180
so 102+48=150 and 180-150=30
Hope this helps