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2 years ago

5

At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs

t two races. If the first race runs 9 horses and the second runs 8, how many different tickets are possible

1 answer:

rewona [7]2 years ago

8 0

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - $^9C_1=9$

Number of ways for second place - $^8C_1=8$

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - $^8C_1=8$

Number of ways for second place - $^7C_1=7$

Total number of different tickets are possible is

$n=9\times 8\times 8\times 7$

$n=4032$

Therefore, 4032 different tickets are possible.

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Step-by-step explanation:

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