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irina [24]
3 years ago
5

At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs

t two races. If the first race runs 9 horses and the second runs 8, how many different tickets are possible
Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

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$50.
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What is six less than 9
Alex73 [517]

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Step-by-step explanation:

9-6=3

4 0
3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
At the beginning of the season, MacDonald had to remove 555 orange trees from his farm. Each of the remaining trees produced 210
nevsk [136]

Answer:

Initial number of trees were 204.

Step-by-step explanation:

555 must be a typo error. The question will not produce correct answer. I worked out with 55 but the answer is wrong. So, the number is 5.

Lets say MacDonald removed 5 orange trees from his farm.

Let t be the initial number of trees

After removing 5 trees, the remaining left are t-5 trees

As given - Each of the remaining trees produced 210 oranges for a total harvest of 41790 oranges. This means

(t-5)210= 41790

Solving for t:

210t-1050=41790

210t=41790+1050

210t=42840

t = 204

So, initial number of trees were 204.

We can check this : 204-5=199

199\times210=41790

------------------------------------------------------------------------------------------

Working with 55 we get the wrong answer:

(t-55)210=41790

210t-11550=41790

210t=30240

t = 144

We can check this : 144-5=139

139\times210=29190  (wrong)

8 0
3 years ago
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