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2 years ago

Point L is on line segment KM. Given LM = 3x + 3,

Mathematics

1 answer:

iris [78.8K]2 years ago

7 0

Answer:

KM = 4

Step-by-step explanation:

$LM = 3x + 3$

$KM = 5x + 4$

$KL = 5x + 1$

$KL + LM = KM$ (segment addition postulate)

$(5x + 1) + (3x + 3) = 5x + 4$ (substitution)

Solve for x

$5x + 1 + 3x + 3 = 5x + 4$

Combine like terms

$8x + 4 = 5x + 4$

$8x + 4 - 4 = 5x + 4 - 4$

$8x = 5x + 0$

$8x - 5x = 0$

$3x = 0$

$x = 0$

$KM = 5x + 4$

Plug in the value of x

$KM = 5(0) + 4$

$KM = 0 + 4 = 4$

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The value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Given the equation y=16- $x^{2}$ and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16- $x^{2}$ from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16- $x^{2}$

Find the integration of 16- $x^{2}$ .

=16x- $x^{3}/3$

Now find the value of integration from x=-1 to x=1.

=16(1)- $(1)^{3}/3$ -16(-1)- $(-1)^{3}/3$

=16(1)-1/3+16-1/3

=32-2/3

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Hence the value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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11 months ago