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4 years ago

What are the solutions to 4(x+5)^2=4?

2 answers:

6 0

First, simplify both sides of the equation: 4x^2 + 40x + 100 = 4. Then, subtract 4 from both sides: 4x^2 + 40x + 96 = 0. Now, you can factor the left side of the equation: 4(x + 4)(x + 6) = 0. You can now set factors to 0, which will leave you x + 4 = 0 and x + 6 = 0. To find x, simply subtract 4 and 6 from both sides. You answer would be x = -4 and x = -6.

aleksandr82 [10.1K]4 years ago

4 0

(X+5)²=4/4
X+5=1, X+5=-1
X=1-5 X=-1-5
X=-4 X=-6

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marissa [1.9K]

Step-by-step explanation:

Consider the provided information.

For the condition statement $p \rightarrow q$ or equivalent "If p then q"

The rule for Converse is: Interchange the two statements.
The rule for Inverse is: Negative both statements.
The rule for Contrapositive is: Negative both statements and interchange them.

Part (A) If it snows tonight, then I will stay at home.

Here p is If it snows tonight, and q is I will stay at home.

Converse: If I will stay at home then it snows tonight.

$q \rightarrow p$

Inverse: If it doesn't snows tonight, then I will not stay at home.

$\sim p \rightarrow \sim q$

Contrapositive: If I will not stay at home then it doesn't snows tonight.

$\sim q \rightarrow \sim p$

Part (B) I go to the beach whenever it is a sunny summer day.

Here p is I go to the beach, and q is it is a sunny summer day.

Converse: It is a sunny summer day whenever I go to the beach.

$q \rightarrow p$

Inverse: I don't go to the beach whenever it is not a sunny summer day.

$\sim p \rightarrow \sim q$

Contrapositive: It is not a sunny summer day whenever I don't go to the beach.

$\sim q \rightarrow \sim p$

Part (C) When I stay up late, it is necessary that I sleep until noon.

P is I sleep until noon and q is I stay up late.

Converse: If I sleep until noon, then it is necessary that i stay up late.

$q \rightarrow p$

Inverse: When I don't stay up late, it is necessary that I don't sleep until noon.

$\sim p \rightarrow \sim q$

Contrapositive: If I don't sleep until noon, then it is not necessary that i stay up late.

$\sim q \rightarrow \sim p$

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