What are the solutions to 4(x+5)^2=4?

2 answers:

6 0

First, simplify both sides of the equation: 4x^2 + 40x + 100 = 4. Then, subtract 4 from both sides: 4x^2 + 40x + 96 = 0. Now, you can factor the left side of the equation: 4(x + 4)(x + 6) = 0. You can now set factors to 0, which will leave you x + 4 = 0 and x + 6 = 0. To find x, simply subtract 4 and 6 from both sides. You answer would be x = -4 and x = -6.

aleksandr82 [10.1K]4 years ago

4 0

(X+5)²=4/4
X+5=1, X+5=-1
X=1-5 X=-1-5
X=-4 X=-6

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Natasha2012 [34]

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3 years ago

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kobusy [5.1K]

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Step-by-step explanation:

3 0

2 years ago

A=(_3 2),b (4 _6),c=(5 _10)

MAXImum [283]

First we find x of p:

$x = 2 \times ( - 3) - \frac{1}{2} \times 4 + \frac{2}{5} \times 5 \\ = - 6 - 2 + 2 = - 6$

then we find y of p:

$y = 2 \times 2 - \frac{1}{2} \times ( - 6) - \frac{2}{5} \times ( - 10) \\ = 4 + 3 + 4 = 11$

so

$p = \binom{ - 6}{11}$

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