Question

What are the solutions to 4(x+5)^2=4?

Answer 1

First, simplify both sides of the equation: 4x^2 + 40x + 100 = 4. Then, subtract 4 from both sides: 4x^2 + 40x + 96 = 0. Now, you can factor the left side of the equation: 4(x + 4)(x + 6) = 0. You can now set factors to 0, which will leave you x + 4 = 0 and x + 6 = 0. To find x, simply subtract 4 and 6 from both sides. You answer would be x = -4 and x = -6.

Answer 2

(X+5)²=4/4
X+5=1,          X+5=-1
X=1-5            X=-1-5
X=-4             X=-6