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4 years ago

Please solve these questions. (Geometry)

Mathematics

1 answer:

son4ous [18]4 years ago

5 0

No idea what this is, sorry

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Given the function below, if h(x) = -1, find x.<br> h(x) = -6 + 20

lions [1.4K]

Answer:

This problem has been solved! See the answer. Suppose f and g are differentiable functions with the values shown in the table below. For each of the following functions h, find h ' (6). x. f ( x) g ( x) f ' ( x) g ' ( x)v

Step-by-step explanation:

7 0

2 years ago

Caleb ran eight laps around a circular track with a diameter of 160 feet how far did he run is 3.14 for pi round answer to the n

chubhunter [2.5K]

Answer:

4021.2ft

Step-by-step explanation:

C=pi•d

C=3.14•160

C=502.65

502.65•8= 4021.2

4 0

2 years ago

7th Grade Math <br><br> Need help with both 6 and 7

barxatty [35]

Answer:

Part 6)

case a) $P(odd)=\frac{1}{2}=0.5=50\%$

case b) $P(less\ than\ 3)=\frac{0}{8}=0=0\%$

Part 7)

case a) $P(yellow)=\frac{3}{20}=0.15=15\%$

case b) $P(green\ and\ red)=\frac{1}{20}=0.05=5\%$

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

Part 6)

case a) P(odd)

In this problem we have

$x=4$

$y=8$

substitute

$P=\frac{4}{8}=\frac{1}{2}=0.5=50\%$

case b) P (less than 3)

In this problem we have

$x=0$

$y=8$

substitute

$P=\frac{0}{8}=0=0\%$

Part 7)

case a) P(yellow)

In this problem we have

$x=3$

$y=20$

substitute

$P=\frac{3}{20}=0.15=15\%$

case b) P(green and red)

$P(green)=\frac{5}{20}$

$P(red)=\frac{4}{20}$

therefore

$P(green\ and\ red)=\frac{5}{20}*\frac{4}{20}=\frac{20}{400}=\frac{1}{20}=0.05=5\%$

8 0

3 years ago

Answer plz:) thank you

sergiy2304 [10]

To find the area of the triangle, you need to do 9*8=72 then divide by 2 to get 36. to find the area of the square you do 5*5=25. subtract 36-25 to get 11. the area of the unshaded region is 11 centimeters squared.

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3 years ago

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What is the standard deviation of the following set of data? 8, 12, 14, 8, 9, 5, 17, 19, 31, 8

Y_Kistochka [10]

5,8,9,12,14,17,19,31

in order

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3 years ago

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