Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Let's turn these into decimals.
so, 10.
0.75
0.50=1/2
0.40
0.20=1/5
In order from least to greatest, these would be:
0.2, 0.4, 0.5, 0.75, 10
Answer:
9 sq ft
Step-by-step explanation:
It's C. When you're dividing g(x) by f(x), you get the equations in both B. and C., but C is more correct because you can't have x=-1/3 because the function is undefined at that number (you can't have the denominator equal 0)
9514 1404 393
Answer:
C. 78°
Step-by-step explanation:
The sum of angles in a triangle is 180°.
(7x-6)° +(4x+11)° +43° = 180°
11x +48 = 180 . . . . . divide by °, simplify
11x = 132 . . . . . . . subtract 48
x = 12 . . . . . . . divide by 11
Then the measure of angle T is ...
∠T = (7x -6)° = (7(12) -6)°
∠T = 78°
