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Galina-37 [17]
3 years ago
11

Help me please.. pleaseeeee

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
5 0
The answer is
34Lb=544oz
5Lb>79oz
Mkey [24]3 years ago
3 0
34lbs=544oz
5lbs>79oz
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If 5 bulbs are $24.95 how much money is 1 bulb?
Elden [556K]

Answer:

4.99

Step-by-step explanation:

If you divide:

$24.95/5bulbs

you get

4.99/1 bulb  

5 0
3 years ago
Complete the table above.
4vir4ik [10]

\bf \begin{array}{|c|c|c|ll}
\cline{1-3}
x&y=3x^2&y=3^x\\
\cline{1-3}&&\\
0&\stackrel{3(0)^2}{0}&\stackrel{3^0}{1}\\&&\\
1&\stackrel{3(1)^2}{3}&\stackrel{3^1}{3}\\&&\\
2&\stackrel{3(2)^2}{12}&\stackrel{3^2}{9}\\&&\\
\cline{1-3}
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4 0
3 years ago
What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?
BabaBlast [244]

slope formula

-10--1/5-2

-9/3

-3

point slope form

y--1=-3(x-2)

y+1=-3x+6

y=-3x+5

5 0
2 years ago
0.01L = how many ML????????
jasenka [17]
Your answer would be ten
5 0
3 years ago
Read 2 more answers
An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually. If the loan is paid in full at the end of
Pavel [41]

Answer:

Given that,

An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually.

To find the Amount paid back after 11 years.

Explanation:

we know that,

The formula to find the,

Amount after n years of interest rate r% compounded annually is,

A=P(1+\frac{r}{100})^n

where P is the initial amount.

Here, we have that,

P=$23,000

r=6.75

n=11

Substitute the values we get,

A=23000(1+\frac{6.75}{100})^{11}

Solving this we get,

A=23000(1+0.0675)^{11}A=23000(1.0675)^{11}A=23000(2.05138)A=47181.805

Round to the nearest dollar.

A=47181.805\approx47182

Answer is: Amount paid back is $47182 after 11 years

7 0
1 year ago
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