6+5=11 5+6=11 11-5=6 11-6=5
Answer:
912.414
Step-by-step explanation:
The angle
θ
between the directions of motion of planes
θ
=
320
−
200
=
120
∘
The distance
a
traveled by first plane flying at a speed of
150
km/hr
in
3
hrs
a
=
150
⋅
3
=
450
k
m
Similarly, the distance
b
traveled by second plane flying at a speed of
200
km/hr
in
3
hrs
b=
200x3=
600 km
Now, the distance between the planes after 3
hrs will be equal to the side of a triangle opposite to the angle θ=120∘
included by the sides
a
=
450
& b=
600
.
Now, using Cosine rule in the concerned triangle, the distance between the plane after
3
hours is given as
Answer:
We have the system:
x ≤ 7
x ≥ a
Now we want to find the possible values of a such that the system has, at least, one solution.
First, we should look at the value of a where the system has only one solution:
We can write the 2 sets as:
a ≤ x
x ≥ 7
So, writing both together:
a ≤ x ≤ 7
if a is larger than 7, we do not have solutions.
then a = 7 gives:
7 ≤ x ≤ 7
Here the only solution is 7.
Now, if a is smaller than 7, for example 5, we have:
5 ≤ x ≤ 7
Now x can take different values, so we have a lot of solutions.
Then the restrictions for a, such that the system has at least one solution, is:
a ≤ 7.
