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Alika [10]
4 years ago
9

Is lmn congruent to opq if so name the postulate

Mathematics
1 answer:
insens350 [35]4 years ago
5 0

Answer:

Option (A)

Step-by-step explanation:

Given:

LM ≅ OP

MN ≅ PQ

∠M ≅ ∠P

To Prove:

ΔLMN ≅ ΔOQP

                   Statements                      Reasons

1). LM ≅ OP                                   1). Given

2). MN ≅ PQ                                 2). Given

3). ∠P ≅  ∠M                                3). Given

4). ΔLNM ≅ ΔOQP                      4). By the SAS postulate of congruence.

                                                         [Side - Angle - Side]                          

Therefore, Option (A) will be the answer.

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STEP 3: Draw the diagonals of the parallelogram. The point where these diagonal lines intersect is the circle's center.

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4 years ago
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timurjin [86]

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3 years ago
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Solve the equation.<br> -21 = (m/3)<br><br> A) m = 7<br> B) m = -7<br> C) m = -63<br> D) m = 63
tiny-mole [99]

Answer:

C) m = -63 is your answer

Step-by-step explanation:

Isolate the variable (m). Note the equal sign, what you do to one side, you do to the other.

Multiply 3 to both sides

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C) m = -63 is your answer

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7 0
3 years ago
A rectangular exercise mat has a perimeter of 36 feet. The length of the mat is twice the width. Write and solve an equation to
Karo-lina-s [1.5K]
<h2>Hello!</h2>

The answers are:

- Length

length=2width=12feet

- Width

width=6feet

- Area

Area=72feet^{2}

<h2>Why?</h2>

We are given the perimeter of a rectangular mat, and we are asked to find the area, and write an equation to determine the length, if feet, of the mat. To solve this problem we need to remember the equation of the perimeter of a rectangle, which is:

Perimeter=2length+2width

Using the given information we have,

36feet=2length+2width

Also, we know that the length is twice the width, so:

length=2width

Then, substituting the second equation into the first equation, we can find the width of the mat.

Substituting, we have:

36feet=2(2width)+2width

36feet=4width+2width

36feet=6width

[tex]\frac{36feet}{6} =width\\width=\frac{36feet}{6} =6feet[/tex]

Then, substituting the width into the second equation, we can find the length of the mat,

Substituting, we have:

length=2width

length=2(6feet)=12feet

Then, finding the area, we have:

A=length*width=12feet*6feet=72feet^{2}

Have a nice day!

7 0
4 years ago
Find the inverse of g(x) = 3x^2 - 5
Arte-miy333 [17]

Answer:

\boxed{\sf \ \ \ g^{-1}(x)=\sqrt{\dfrac{x+5}{3}} \ \ \ }

Step-by-step explanation:

Hello,

x=(gog^{-1})(x)=g(g^{-1}(x))=3(g^{-1}(x))^2-5\\\\3(g^{-1}(x))^2 = x+5\\\\\\ (g^{-1}(x))^2=\dfrac{x+5}{3}\\g^{-1}(x)=\sqrt{\dfrac{x+5}{3}}

hope this helps

8 0
3 years ago
Read 2 more answers
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