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crimeas [40]
2 years ago
10

Help me solve this problem please

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
8 0

Answer:

actually what is this is you is this a geometry, trigonometry I don't know what to call

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Find the sum of the arithmetic sequence.<br><br> -10, -7, -4, -1, 2, 5, 8
Lesechka [4]

Answer:

+3 every time or the total?

Or is it 18? U specify which

7 0
3 years ago
Brian has reduced his cholesterol level by 20% by following a strict diet and regular exercise. If his original level was 220, w
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220 x 20% (.20) = 44
220-44=176
3 0
3 years ago
Read 2 more answers
Elasticity of Demand The demand function for a certain brand of backpacks is
Trava [24]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:

                           P ( x ) = 50 Ln ( 50 / x ).

- The point price elasticity ( E ) of demand is given by:

                           E = \frac{P}{x}*\frac{dP}{dx}  

- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.

- To determine the " dP / dx " by taking the first derivative of the given relation:

                          P ( x ) = 50 Ln ( 50 / x ).

                          d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]

                                              = - 50 / x

- Hence the point price elasticity of demand is given by:

                          E = - ( P / x ) * ( 50 / x )

                          E = -50*P / x^2    

- For an inelastic demand, ! E ! is < 1:

                          ! -50*P / x^2 ! < 1

                          50*P / x^2 < 1

                          P < x^2 / 50

- For an unitary demand, ! E ! is =  1:

                          ! -50*P / x^2 !  = 1

                          50*P / x^2 = 1

                          P = x^2 / 50

- For an inelastic demand, ! E ! is > 1:

                          ! -50*P / x^2 ! > 1

                          50*P / x^2 > 1

                          P > x^2 / 50

2)

If the unit price is increased slightly from $50, will the revenue increase or decrease?

- We see from the calculated demand sensitivity d P / dt:

                          d P ( x ) / dx = - 50 / x

- We see that as P increases the from P = $50, the quantity of goods demanded would be:

                          50 = 50 ln(50/x)

                           1 = Ln ( 50 / x )

                           50/x = e

                           x = 50 / e

Then,

                          d P ( x ) / dx = - 50 / ( 50 / e )

                          d P ( x ) / dx = - e

- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.

- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:

                Revenue R ( x ) = P ( x ) * x

                                = 50*x*ln(50/x)

Then the product of price and quantity goods also decreases; hence, revenue decreases.

8 0
3 years ago
2.34 x 10^65   + 9.2 x10^66  
vivado [14]

Answer:

9.434 X 10^66

Step-by-step explanation:

2.34 X 10^65  +  9.2 X 10^66    (First, you have to manipulate the exponents to bring them to the same index, i.e. the same power)

We can say that 2.34 X 10^65 = 0.234 X 10^66

Now that the indexes are equivalent, we can proceed to add the two bases together.

0.234 X 10^66  +  9.2 X 10^66

= (0.234  +  9.2) X 10^66

= 9.434 X 10^66

3 0
3 years ago
In a right triangle, Sin (30 + x) º = Cos (3x) º. What is the value of x?
pogonyaev

Answer:

x=15^\circ

Step-by-step explanation:

In a right triangle:

\sin \theta =cos(90^\circ-\theta) $ (Complementary angles)

Therefore, given:

Sin (30 + x) \º = Cos (3x) \º\\30+x+3x=90^\circ\\30+4x=90^\circ\\4x=90^\circ-30^\circ\\4x=60^\circ\\$Divide both sides by 4\\x=15^\circ

5 0
3 years ago
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