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photoshop1234 [79]
3 years ago
15

Find the factors of the following numbers. a) 15 b) 22 c) 34 d) 45 e) 50

Mathematics
1 answer:
slega [8]3 years ago
3 0

Answer:

1,3,5,15

1,2,11,22

1,2,17,34

1,3,5,9,15,45

1,2,5,10,25,50

Step-by-step explanation:

Hope it will help u

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Which of the following equations is direct variation? Y=2x,y=x+2,y=2,y=-2x-1
Andrew [12]

Answer:

y=2x

Step-by-step explanation:

Direct variation is such that y=kx where k is the rate of change.  In direct variation the graph must cross the origin (0,0) meaning that the y-intercept is zero.  The only equation that satisfies the definition of direct variation is y=2x.

3 0
3 years ago
Find the circumference of the object. Use 3.14 or 22/7
dmitriy555 [2]
C=2pi r
C = 2 pi 7
C= 14 pi
C= 43.96 in
4 0
3 years ago
In body paragraph 1, how many times is evidence (‘SAY”) cited? B) Same article? Yes or No
marshall27 [118]

Answer:

Down below hope it helps :)

Step-by-step explanation:

The evidence "SAY" was only written once. It wasn't by the same article, the writer introduces two separate articles.

Kinda confused by this question but I think that's the answer.

5 0
2 years ago
What is the value of x in 145.95-2x=-4.05?
kotykmax [81]
145.95 - 2x = -4.05
subtract -145.95 from both side of the equation
-2x = -4.05 - 145.95
-2x = -150
Divide both sides by -2
-2x/2 = -150/2

x = 75
Final answer

Hope this helps!!!!
3 0
3 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
3 years ago
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