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3 years ago

Why is it important to include the units in a rate

Mathematics

1 answer:

bija089 [108]3 years ago

7 0

Answer:

Unit rates are useful because they allow you to make direct comparisons. For example, you have your choice between two bottles of ketchup.

Step-by-step explanation:

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What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction? Take the square root of both

balu736 [363]

Answer:

The first step is

Take the square root of both sides of the equation

Step-by-step explanation:

we have

$x^{2} =\frac{9}{16}$

Solve for x

step 1

Take square root both sides

$x=(+/-)\frac{3}{4}$

the solutions are

$x=+\frac{3}{4}$ and $x=-\frac{3}{4}$

therefore

The first step is

Take the square root of both sides of the equation

5 0

2 years ago

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There are 1073 students at Raine High School. 26 percent do not identify as male or female, 42 percent identify as female, and 3

irinina [24]

Don’t Identify- 278.98
Female- 450.66
Male- 343.36

Considering these are people, you probably will need to round either up or down. If you round it would be:

Don’t Identify- 279
Female- 451
Male- 343

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2 years ago

Michael earns $8 an hour to baby sit the Jackson family. How many hours does he have to 1 point

notsponge [240]

Answer:

7 hours

Step-by-step explanation:

56/8=7

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3 years ago

line AB has endpoints A (-3, 1) and B (4, 5), find the coordinates of point p on directed line segment AB that partitions AB in

Margarita [4]

<h3>Given</h3>

A(-3, 1), B(4, 5)

coordinates of P on AB such that AP/PB = 5/2

<h3>Solution</h3>

AP/PB = 5/2 . . . . . desired result

2AP = 5PB . . . . . . multiply by 2PB

2(P-A) = 5(B-P) . . . meaning of the above

2P -2A = 5B -5P . . eliminate parentheses

7P = 2A +5B . . . . . collect P terms

P = (2A +5B)/7 . . . .divide by the coefficient of P

P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points

P = (-6+20, 2+25)/7 . . . . . . simplify

P = (2, 3 6/7)

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3 years ago

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Simplify, Write your answer in exponential notation.<br> a.) 2³ x 2-5<br> b.) (602)3

mariarad [96]

The simplified expressions are 2^-2 and 60^6

<h3>How to simplify the expressions?</h3>

<u>Expression (a)</u>

We have:

2^3 * 2^-5

Apply the product law of indices

2^3 * 2^-5 = 2^(3 - 5)

Evaluate the difference

2^3 * 2^-5 = 2^-2

<u>Expression (b)</u>

We have:

(60^2)^3

Apply the power law of indices

(60^2)^3 = 60^(2 * 3)

Evaluate the product

(60^2)^3 = 60^6

Hence, the simplified expressions are 2^-2 and 60^6