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Alja [10]
3 years ago
8

Given that an intercepted arc has length 6pi inches and a central angle is pi/3, find the radius

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0
\bf \textit{arc's length}\\\\
s=r\theta \quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
s=6\pi \\
\theta =\frac{\pi }{3}
\end{cases}\implies 6\pi =r\left( \frac{\pi }{3} \right)\implies \cfrac{6\pi }{\frac{\pi }{3}}=r
\\\\\\
\cfrac{6\pi }{1}\cdot \cfrac{3}{\pi }=r\implies 18=r
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I don’t get this one but the question was something about finding the equation.
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Answer:

  y = -(x -3)^2 +2

Step-by-step explanation:

The vertex form of the equation for a parabola is ...

  y = a(x -h)^2 +k

where the vertex is (h, k) and the value 'a' is a vertical scale factor.

The value of 'a' can be found by looking at the y-value of points ±1 either side of the vertex relative to the vertex. Here, the vertex y-value is +2 at x=3, and either side goes down 1 unit (to y=1) for 1 unit to the right or left. So, a = -1.

Using the values we've read from the graph for the vertex (h, k) = (3, 2) and the scale factor a = -1, we can write the equation as ...

  y = -(x -3)^2 +2

4 0
3 years ago
A scientist calculated the mean and standard deviation of a data set to be = 120 and 0-9. She then found that she was
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Step-by-step explanation:

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2 years ago
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

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Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
Please help <br> The diagram shows a 5ft student standing near a tree
Novosadov [1.4K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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MatroZZZ [7]
2 divided by 18 is 9 and 3 divided by 18 is 6 hope that helps
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