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Reika [66]
3 years ago
14

what is the area of the shaded sector of the circle if the radius is 14 ft? leave your answer in terms of pi

Mathematics
1 answer:
Strike441 [17]3 years ago
3 0

Given:

Radius = 14 ft

θ = 45°

To find:

Area of the shaded sector

Solution:

Area of the sector formula:

$\text { area of sector }=\frac{\theta}{360^{\circ}} \times \pi r^{2}

                      $=\frac{45^\circ}{360^{\circ}} \times \pi \times 14^{2}

                      $=\frac{1}{8} \times \pi \times 196

                      =24.5\pi ft²

The area of the shaded sector of a circle is 24.5π ft².

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Jeff has a density of 1000 g/mL and a volume of 25-mL. What is Jeff’s mass?
zlopas [31]

Answer:

25,000 grams

Step-by-step explanation:

Density can be found using the following formula:

d=\frac{m}{v}

If we rearrange the formula for m, mass, we will multiply both sides of the equation by v.

d*v=\frac{m}{v}*v

d*v=m

The mass can be found by multiplying the density by the volume.

Jeff's density is 1000 grams per milliliter and his volume is 25 milliliters.

d= 1000 g/mL\\v=25 mL

Substitute the values into the formula.

m=d*v

m= 1000 g/mL * 25 mL

Multiply. When you multiply, the "mL" or milliliters will cancel out.

m= 1000 g * 25

m= 25000 g

Jeff's mass is 25,000 grams.

6 0
3 years ago
Evaluate 8+3e when e= 2.
trapecia [35]

\text{Hey there!}

\text{If e = 2 then replace the e in the equation to 2}

\mathsf{8+3e}\\\mathsf{= 8+3(2)}\\\mathsf{3(2)=6}\\\mathsf{8+6=14}\\\\\boxed{\boxed{\mathsf{Answer: \boxed{\mathsf{14}}}}}\checkmark

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5 0
3 years ago
Read 2 more answers
Solve by using related function 1/2x^2 -2=0
Thepotemich [5.8K]

Answer:

1/2x^2-2=0

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x=2,-2

4 0
3 years ago
How do I solve for y=160x+2=y=280x-3?
mrs_skeptik [129]
Answer (5/264,76/33)
5 0
2 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

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1 year ago
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