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1 year ago

Find the slope of the line that passes through the two points. (3, 4) and (5, 7)

Mathematics

2 answers:

Luda [366]1 year ago

7 0

Answer:

what

Step-by-step explanation:

Alexxx [7]1 year ago

6 0

Answer: The answer is $\frac{7-5}{4-3}$ = $\frac{2}{1}$ =2

The formula to solve down here:

(x1,y1)

(x2,y2)

Step-by-step explanation:

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Please help on math hw will mark brainliest

erma4kov [3.2K]

Answer:

∠ACB 107°

Step-by-step explanation:

1.) First, by using straight angle theorem we can determine that ∠CED is equal to 180 - 147 which is 33°.

2.) Next, using alternate interior angles theorem we know that ∠CDE = ∠ABC which is 40°

3.) Then, because of the angle sum theorem we know that all the angles of the triangle must add to 180° and we can therefore solve for ∠DCE using the equation 33 + 40 + x = 180 where x is ∠DCE. By solving this we get 107°.

4.) Finally, using vertical angles theorem we know that ∠DCE = ∠ACB and so ∠ACB is 107°

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3 years ago

at a restaurant 6 hot dogs cost $8.28 and 7 hamburgers cost $9.24. which food has the lower unit price?

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Step-by-step explanation: Hamburgers

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3 years ago

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3 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

Find the slope of the line that passes through the two points. (3, 4) and (5, 7)​

Find the slope of the line that passes through the two points. (3, 4) and (5, 7)