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3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

Maslowich3 years ago

3 0

Step-by-step explanation:

$\displaystyle y = Asin(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the midline where the amplitude is.

I am joyous to assist you anytime.

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Tisa and Paloma are measuring different lengths of sidewalk.

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Answer:

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Step-by-step explanation:

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3 years ago

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Find the area of the semicircle please .

NeX [460]

Answer:

39.25

Step-by-step explanation:

the formula is a = (3.14 × $r^{2}$ ) / 2

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1. $5^{2}$ = 25

2. 3.14 × 25 = 78.5

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I hope this helped! :)

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3 years ago

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Whats the absoulte value of -5

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The absolute value of -5 would be 5

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3 years ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

The sum of three consecutive even integers is 108. What is the largest number?

horrorfan [7]

Answer:

The largest of three numbers is 38.

Step-by-step explanation:

Given : The sum of three consecutive even integers is 108.

We have to find the largest of three consecutive even integer.

Consecutive integers are integer having a difference of one between each term . example 14 , 15, 16 ..

consecutive even integers are integers having a difference of two between them such that first term is in the form of 2n , where n is integers.

Consider the three consecutive even integers are 2n , 2n + 2 , 2n + 4

Also, given The sum of three consecutive even integers is 108.

that is 2n + 2n + 2 + 2n + 4 = 108

Simplify, we get,

6n + 6 = 108

Subtract 6 both side, we get,

6n = 102

Divide by 6 both side, we get,

n = 17

Thus, numbers are 2n = 2 × 17 = 34

2n + 2 = 34 + 2 = 36

2n + 4 = 34 + 4 = 38

Thus, The sum of three consecutive even integers is 108 then integers are 34, 36, 38 .

Thus, The largest of three numbers is 38.

3 0

3 years ago