All categories

3 years ago

How can the statement below be rewritten as a conditional statement in if-then form?

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

Answer:

<h2>If two angles measures 180 degrees, then they form a linear pair.</h2>

Step-by-step explanation:

The conditional statement should be this way, because after the word ''if'', should be placed the condition, and after the word ''then'', should be the consequence.

You might be interested in

Darlene wants to buy a sweater that originally cost 32$ it is on sale for 20% off. Sales tax is 6.75%. What is the final price o

AURORKA [14]

Answer:

Step-by-step explanation:

32 x 0.20 = $6.40

32 - 6.4 = $25.60

25.6 x .0675 ≈ 1.738

25.6 + 1.738 = 27.338 ≈$27.34

6 0

3 years ago

Please help with these questions... I've been trying to figure them out for like twenty minutes and at this point I just don't h

vlada-n [284]

Answer:

1. y=2x^2-8X-1

2. y=-6x^2+36x-63

3. y=-3x^2+18x-34

4. y=9x^2+54x+76

5. y=-x^2+8x-22

6. y=6x^2-48x+90

7. y=8x^2+16x+5

8. y=2x^2-8x+1

Have a great day :)

3 0

2 years ago

100 PTS!! Will give Brainliest...

nydimaria [60]

Answer:

shifted left 7 & shifted down 3

Step-by-step explanation:

8 0

2 years ago

Approximate the change in the volume of a sphere when its radius changes from r = 40 ft to r equals 40.05 ft (Upper V (r )equal

alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere ( $V$ ), measured in cubic feet, is represented by the following formula:

$V = \frac{4\pi}{3}\cdot r^{3}$

Where $r$ is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

$\Delta V = \frac{\partial V}{\partial r}\Delta r$

The derivative of the volume as a function of radius is:

$\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}$

Then, the change in volume is expanded:

$\Delta V = 4\pi \cdot r^{2}\cdot \Delta r$

If $r = 40\,ft$ and $\Delta r = 40\,ft-40.05\,ft = 0.05\,ft$ , the change in the volume of the sphere is approximately:

$\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)$

$\Delta V \approx 1005.310\,ft^{3}$

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0

2 years ago

What is m∠1 if m∠7 = 60°?

inna [77]

Step-by-step explanation:

95vxgr Tu fjvgzgvkvgshvysrvv

6 0

3 years ago