Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
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How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
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Answer:
It should be 0.012566 rounded
Step-by-step explanation:
Answer:
0.15401
Step-by-step explanation:
Given that test statistic = 3.7408
From the question, we could deduce that, this is scenario could be analysed A ONE - WAY analysis of Variance method as it has one independent variable, Age subdivided into 3 levels
The test statistic value obtained is the Chisquare (χ²) value, which equals 3.7408
To Obtain the requested Pvalue, we need the degree of freedom, which is :
(Number of columns - 1) * (number of rows - 1)
Number of candidates = 2
Number of levels = 3
Hence,
Degree of freedom = (3 - 1) * (2 - 1) = 2 * 1 = 2
Using the Chisquare Pvalue calculator or distribution table :
χ²;3.7408, 2 = 0.154062
Pvalue = 0.1541
0, 1/3, 2/3, 1, 1 1/3, 1 2/3, 2
