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3 years ago

PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!

Mathematics

2 answers:

Oksana_A [137]3 years ago

6 0

X would be less than or equal to 6 since 58-4 is 54 and that’s equal to 9x so divide by 9, equaling 6. X would be more than 30 since 3+2 is 5 and multiplied by 6 is 30

Leona [35]3 years ago

5 0

9x + 4 ≤ 58

=> 9x ≤ 58 - 4

=> 9x ≤ 54

=> x ≤ 54/9

=> x ≤ 6
______________

1/6x − 2 > 3

=> 1/6x > 3 + 2

=> 1/6x > 5

=> x > 5×6

=> x > 30

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In triangle ABC, angle A measures 40º and angle B measures 60º. In triangle PQR, angle P measures 40º and angle Q measures 80º.

Soloha48 [4]

Answer:

Latoya's statement because they are similar not congruent

4 0

2 years ago

HELP PLEASE!!!!! IT DOESN'T EVEN SHOW UP ON GOOGLE!!!!!!!!!!!!!1

meriva

0.032 is the interest
since it is half a year, double this one
0.032 x 2 = 0.064

your formula is A = P(1 + (r/n)^nt
P is principle
R is rate
N is number of times
T is time

A = 32,675.12(1 + (0.032/2)^2(5)
A = 32675.12(1 + (0.016)^10
A = 32675.12(1.016)^10
A = 32675.12 (1.172)
A = 38295.24064
Your answer is ~38295.24

hope this helps

none of the answers make sense, because you can withdraw a lot more money from your bank account than that, unless you are missing some numbers and stuff

5 0

3 years ago

Read 2 more answers

You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 2 or getting heads

tino4ka555 [31]

P(2 or H) = P(2) + P(H) - P(2 and H)

What is the probability of getting a 2 P(2)? = 1/6

What is the probability of getting heads P(H)? = 1/2

P(2 and H) is the product of those two events since the events are independent. = 1/6 * 1/2 = 1/12

P(2 or H) = P(2) + P(H) - P(2 and H)

P(2 or H) = 1/6 + 1/2 - 1/12 = 7/12

5 0

3 years ago

Are the data shown in this line plot skewed left, skewed right, or not skewed?

alukav5142 [94]

Not skewed, I can tell dawgggg ooooohhhhh and I’m wasted

4 0

3 years ago

A population of monkeys' tail lengths is normally distributed with a mean of 25 cm with a standard deviation of 8 cm. I am prepa

Crank

Answer:

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = 0.4772

Step-by-step explanation:

Step(i):-

Given mean of the Population 'μ'= 25c.m

Given standard deviation of the Population 'σ' = 8c.m

Given sample size 'n' = 256

Let X₁ = 24

$Z_{1} = \frac{x_{1}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{24-25}{\frac{8}{\sqrt{256} } } = -2$

Let X₂ = 25

$Z_{2} = \frac{x_{2}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{25-25}{\frac{8}{\sqrt{256} } } = 0$

Step(ii):-

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = P(-2≤ Z ≤0)

= P( Z≤0) - P(Z≤-2)

= 0.5 + A(0) - (0.5- A(-2))

= A(0) + A(2) ( ∵A(-2) =A(2)

= 0.000+ 0.4772

= 0.4772

Final answer:-

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = 0.4772

4 0

3 years ago