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katovenus [111]
3 years ago
12

A theater group made appearances in two cities. The hotel charge before tax in the second city was $1500 lower than in the first

. The tax in the first city was
7.5%, and the tax in the second city was 7%. The total hotel tax paid for the two cities was $547.50. How much was the hotel charge in each city before tax?
Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

let the hotel charge before tax for second hotel be x

then the hotel charge before tax for first hotel = x+1500

tax of first hotel = 7.5% * (x+1500) = (7.5x+11250)/100

tax from second hotel= 7% of x = 7x/100

total tax = 547.50

7x/100 + (7.5x+11250)/100 =547.50

14.5x = 54750-11250

14.5x= 43500

x= 3000

hotel charge in first city = 4500

in second city =3000

Step-by-step explanation:

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Answer:

1. x = 18.4

2. x = -1.25

3. x = \frac{5}{12}

4. x = 12.3

5. x = 6.4

6. z = 5.8

7. x = \frac{1}{12}

8. x = -\frac{1}{4}

9. x = \frac{1}{3}

10. x = -9

11. z = 18

12. x = 7

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18. x = -\frac{45}{7}

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21. x = \frac{8}{3}

22. x = -1.6

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24. x = -8.2

Step-by-step explanation:

1. x - 3.5 = 14.9 (add 3.5 to each side)

x = 18.4

2. x + 2.25 = 1 (subtract 2.25 from each side)

x = -1.25

3. -\frac{1}{3} = x - \frac{3}{4} (add \frac{3}{4} to each side)

\frac{3}{4} - \frac{1}{3}  = x (multiply \frac{3}{4} by \frac{3}{3} and \frac{1}{3} by \frac{4}{4} to get a common denominator)

\frac{9}{12} - \frac{4}{12} = x

\frac{5}{12} = x

4. x - 2.8 = 9.5 (add 2.8 to each side)

x = 12.3

5. x - 8.5 = -2.1 (add 8.5 to each side)

x = 6.4

6. z - 9.4 = -3.6 (add 9.4 to each side)

z = 5.8

7. x + \frac{5}{6} = \frac{11}{12} (subtract \frac{5}{6} from each side)

x = \frac{11}{12} - \frac{5}{6} (multiply \frac{5}{6} by \frac{2}{2} to get a common denominator)

x = \frac{11}{12} - \frac{10}{12}

x = \frac{1}{12}

8. -\frac{5}{6} + x = -\frac{13}{12} (add \frac{5}{6} to each side)

x = \frac{5}{6} - \frac{13}{12} (multiply \frac{5}{6} by \frac{2}{2} to get a common denominator)

x = \frac{10}{12} - \frac{13}{12}

x = -\frac{3}{12} = -\frac{1}{4}

9. x - \frac{1}{9} = \frac{5}{18} (add \frac{1}{9} to each side)

x = \frac{1}{9} + \frac{5}{18} (multiply \frac{1}{9} by \frac{2}{2} to get a common denominator)

x = \frac{2}{18} + \frac{5}{18}

x = \frac{6}{18} = \frac{3}{9} = \frac{1}{3}

10. x + 6 = -3 (subtract 6 from each side)

x = -9

11. z - 7 = 11 (add 7 to each side)

z = 18

12. -1 = x - 8 (add 8 to each side)

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13. -4x = 36 (divide each side by -4)

x = -9

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x = -36

15. 63 = -9x (divide each side by -9)

-7 = x

16. 6.4 = 0.8x (divide each side by 0.8)

8 = x

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x = -12

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x = -\frac{7}{8} ÷ -\frac{21}{64}

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x = -1.6

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1.8 = x

24. -2.5x = 20.5 (divide each side by -2.5)

x = -8.2

3 0
3 years ago
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Which point is on the line that passes through (0,6) and is parallel to the given line? plzz helppp!
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You can check this because parallel lines have the same slope so

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Line 1:  -4 - (-2) / 0 - (-12) = -2/12 = -1/6

Line 2:  6 - 8 / 0 - (-12) = -2/12 = -1/6


5 0
3 years ago
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