W(x) = 5^2x + 1; Find w(0)
1 answer:
Answer:
w(0) = 1
Step-by-step explanation:
If w(0) is true, replace all x in the equation with 0 and then solve
w(0) = 5^2(0) + 1
w(0) = 25(0) + 1
w(0) = 0+1
w(0) = 1
You might be interested in
thats cool did you want to ask a question though?
Answer:
Part A
16y = 7x + 101
Part B
3y = 5x + 30
Part C
y = -5x/3
Part D
x = -3
(2.6 * 10^9) / (1.3 * 10^2) =
(2.6 / 1.3) * (10^9) / (10^2) =
2 * 10^7 or 20,000,000 <===
The scale factor is positive 4.