The answer
A:6.09
Th explanation
Divide 24.36 by 4 and that’s what you get
Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
Children ticket price=£9
Adult ticket price=£17
Let adult=A
Children=C
So, 2A+3C=61 (equation 1)
3A+5C=96(equation 2)
Multiply equation 1 by 3 and equation 2 by 2
Solve equations and get the answer.
Answer:
Step-by-step explanation:
It would add a 0
Answer:
First we need to calculate the distance between Clifton and Burlington by using Pythagorean theorem:
x² + 65² = 97²
=> x² = 97² - 65²
=> x² = 5184
=> x = √5184 = 72 (m)
The total distance from Aurora to Clifton through Burlington is: 65 + 72 = 137 (m)
We have: 137 - 97 = 40 (m)
So it is 40 m closer to travel from Aurora to Clifton directly than from Aurora to Clifton through Burlington
