Around 5.4572271...% decrease
(i’m not sure what to round it to)
subtract 192,300 from 203,400 to find the amount of change
(= 11,100)
then divide that amount from the original price (203,400)
then multiply that number by 100 to get a percent
finally round to a reasonable percent
Here,a(n) = a + (n-1)d
Here, a = 5, d = 12-5 = 8, a(n) = 181
Substitute this values in to the expression,
181 = 5 + (n-1)8
181-5 = 8n-8
176+8 = 8n
n = 184/8
n = 23
So, it is 23th term of that Arithmetic Progression.
Hope this helps!
Coolio
lw=1000
lets assume that the aluminum sides are the legnth
2 sides
2*15=30
30l=cost of aluminum
steel=10w
wood=(w-10)5=5w-50
we can eliminate the w by solving for w in first relation
lw=1000
divide both sides by l
w=1000/l
sub that for w
10(1000/l)=steel
5(1000/l)-50=wood
wood cost+steel+aluminum cost=total cost
10(1000/l)+5(1000/l)-50+30l=1525
(10000/l)+(5000/l)-50+30l=1525
(15000/l)-50+30l=1525
add 50 to both sides
(15000/l)+30l=1575
times both sides by l
15000+30l²=1575l
minus 1575l from both sides
30l²-1575l+15000=0
factor
(15)(l-40)(2l-25)=0
set each equal to 0
l-40=0
l=40
2l-25=0
2l=25
l=12.5
the there are 2 possible combinations
aluminum=40yd and steel=25yd or
aluminum=12.5yd and steel=80ft
both yield 1000yd² and cost $1525
1/3 part of strawberry juice per 1 part of lemon juice
Answer:
Number of rocks and fossils collected by you is 1 and 24 respectively
Number of rocks and fossils collected by your friend is 3 and 12 respectively
Step-by-step explanation:
Let the number of Rocks you collect be x
Let the number of Fossils you collect be y
Then the total number pf objects you collected will be
x + y = 25
x = 25 - y------------------------------(1)
Your friend collects three times as many rocks and half as many fossils as you.
This can be written as

-------------------(2)
Substituting (1) in (2)


Grouping the like terms we get,





y= 24
Substituting y value in equation(1) we get
x = 25 - 24
x= 1
Friends collects 3 times rock
so collects 3x =3(1) = 3rocks
Also he collects half as many fossils
That is
