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Answer:
![\mathtt{The \ efficiency \ of \ photosynthesis =1.08 \%}](https://tex.z-dn.net/?f=%5Cmathtt%7BThe%20%5C%20efficiency%20%5C%20of%20%20%5C%20photosynthesis%20%3D1.08%20%5C%25%7D)
Explanation:
Given that:
the quantity of solar radiation = 7,000,000cal/m²/day
The producers' gross productivity in the salt marsh (mostly microscopic algae) is 0.0040 g/cm²/day.
= 0.004 × 2920 cal × 10000 m²/ day
= 116800 cal/m²/day
The respiration requirement is 35% of the gross primary productivity.
i.e 35% of 116800 calories/m²/day
=
calories/m²/day
= 40880 calories/m²/day
The Net primary productivity NPP = Gross productivity - Respiration requirement
=( 116800 - 40880)
calories/m²/day
= 75920 calories/m²/day
We can calculate the efficiency of photosynthesis by using the formula:
![\mathtt{The \ efficiency \ of \ photosynthesis = \dfrac{ Net \ primary \ productivity \ NPP}{quantity \ of \ solar \ radation} \times 100\%}](https://tex.z-dn.net/?f=%5Cmathtt%7BThe%20%5C%20efficiency%20%5C%20of%20%20%5C%20photosynthesis%20%3D%20%5Cdfrac%7B%20Net%20%5C%20primary%20%5C%20productivity%20%5C%20NPP%7D%7Bquantity%20%20%5C%20of%20%5C%20solar%20%5C%20radation%7D%20%5Ctimes%20100%5C%25%7D)
![\mathtt{The \ efficiency \ of \ photosynthesis = \dfrac{ 75920 \ cal/m^2/day}{7000000 \ cal/m^2/day} \times 100\%}](https://tex.z-dn.net/?f=%5Cmathtt%7BThe%20%5C%20efficiency%20%5C%20of%20%20%5C%20photosynthesis%20%3D%20%5Cdfrac%7B%2075920%20%5C%20%20cal%2Fm%5E2%2Fday%7D%7B7000000%20%5C%20cal%2Fm%5E2%2Fday%7D%20%5Ctimes%20100%5C%25%7D)
![\mathtt{The \ efficiency \ of \ photosynthesis =1.08 \%}](https://tex.z-dn.net/?f=%5Cmathtt%7BThe%20%5C%20efficiency%20%5C%20of%20%20%5C%20photosynthesis%20%3D1.08%20%5C%25%7D)
Answer:
hjalmar schcht, franz van papen, hans fritzsche
Explanation:
hope this helps :)