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3 years ago

Help please, I'm stuck i tried answering it but can't really understand it.

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

Answer:

B. None

Step-by-step explanation:

We can use substitution for this.

First solve the first equation for y:

y + 7x = -3

y = -7x - 3

Now, substitute this expression in for y in the second equation:

14x + 2(-7x - 3) = 6

We can then solve for x:

14x - 14x - 6 = 6

0 - 6 = 6

-6 = 6

However, we know that -6 ≠ 6, so there are no solutions to this system. Thus, the answer is B, none.

Hope this helps!

Ray Of Light [21]3 years ago

3 0

Answer:

no solutions

Step-by-step explanation:

y+7x =-3

14x+2y = 6

Multiply the first equation by -2 to eliminate x and y

-2y-14x = 6

14x+2y = 6

--------------------------

0 = 12

This is never true, so there are no solutions

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Is 8.47 greater than or less than 8.63

Murljashka [212]

Answer:

8.47 is less than 8.63

Step-by-step explanation:

Although they both contain the number 8, if you look at the decimals, 63 is more than 47. Hence, 8.47 is less than 8.63.

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4 years ago

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A small bowl of candy holds 75% as much as a large bowl of candy.

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Answer:

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Step-by-step explanation:

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3 years ago

The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0

3 years ago

Please i need help asap please this is for a final please

ELEN [110]

Answer:

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Step-by-step explanation:

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andrey2020 [161]

Answer:

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Step-by-step explanation:

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3 years ago