Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
C
Step-by-step explanation:
The original is L, if it was roated 180 degrees clockwise it would be in the same spot
Answer:
Multiply each measurement by 2 then add them together
OR
Add 7 + 3 and multiply by 2
Step-by-step explanation:
Answer would be 20ft
Answer:
d
Step-by-step explanation:
A. it is a hexagon (there are 6 sides) B. using the equation (n-2)180 (where n is the number of sides we get (6-2)180=4*180=720. divide 720 by 6 to get 120 for each angle of the hexagon. (it has no irregularities in it's shape so that number will be correct for them all.) C. to get that just divide 39 by 6 to get 6.5 in per side. Hope that helps:)