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4 years ago

15

If y varies directly as x and z, and y=40 when x=5 and z=4, find y when x=2 and z=1

1 answer:

kodGreya [7K]4 years ago

3 0

Answer:y=4

Step-by-step explanation:

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Find the values of x and y that satisfy the equation.

HACTEHA [7]

Answer:

x=-5-2yi/3+4i

y=3xi/2+6+15i/2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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3 years ago

How can I show that 0 is not a natural number

madam [21]

Answer:

The reason why 0 is not a natural number is because does not have a value which is positive or negative. Therefore, since all real numbers are positive integers, we do not assume that zero is a natural number. Although zero is called a number in its entirety.

Step-by-step explanation:

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3 years ago

Brandon wants to conduct a survey as to whether mushrooms should be added

katen-ka-za [31]

I think the answer is D: interview every student who eats lunch in the cafeteria

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2 years ago

A segment has endpoint of 5,21 and 3,15 what are the coordinates of the midpoint of the segment

son4ous [18]

Answer:

(4, 18)

Step-by-step explanation:

(5 + 3)/2 = 8/2 = 4

(21 + 15)/2 = 36/2 = 18

Answer: (4, 18)

7 0

3 years ago

Read 2 more answers

A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th

pochemuha

Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

<em>The actual dimension is 18.28 by 3.28</em>

3 0

3 years ago