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3 years ago

Need help with this question please!!

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

$\displaystyle\\\tan x=1\\ 0^o$

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Which set of numbers could be the side length of a right tirangle

Crank

Answer:

Step-by-step explanation:

3x4=12

12/2=6

3,4,6

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3 years ago

For which pair of points can you use this number line to find the distance?

Brilliant_brown [7]

Answer:

(2,0) and (2,3)

Step-by-step explanation:

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3 years ago

ACDF is a trapezoid and

Sholpan [36]

Answer:

x = 7

Step-by-step explanation:

See the attached figure.

As shown: A C D F is a trapezoid and BE is a mid-segment.

The mid-segment of the trapezoid is the average of its bases.

BE = 0.5 ( A F + C D)

Given: CD = 18 , BE = 2x + 10 and A F = 6x - 12

So,

2x + 10 = 0.5 ( 18 + 6x - 12)

Solve for x

2x + 10 = 0.5 (6 + 6x)

2x + 10 = 3 + 3x

10 - 3 = 3x - 2x

∴ x = 7

So, the value of x is 7

8 0

3 years ago

Elimination_4x_2y=14 _10x+7y=_24

Gnesinka [82]

Answer:

The answer is $x=-\frac{50}{8}$ and $y=\frac{11}{2}.$

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

$-4x-2y=14$ ......(1)

$-10x+7y=-24$ ......(2)

So, we multiply the equation (1) by 7 we get:

$-28x-14y=98$

And, we multiply the equation (2) by 2 we get:

$-20x+14y=-48$

Now, adding both the new equations:

$-28x-14y+(-20x+14y)=98+(-48)$

$-28x-14y-20x+14y=98-48$

$-28x-20x-14y+14y=50$

$-8x=50$

Dividing both the sides by -8 we get:

$x=-\frac{50}{8}$

Now, putting the value of $x$ in equation (1):

$-4x-2y=14$

$-4(-\frac{50}{8})-2y=14$

$\frac{200}{8} -2y=14$

$25-2y=14$

Subtracting both sides by 25 we get:

$-2y=-11$

Dividing both sides by -2 we get:

$y=\frac{11}{2}$

Therefore, the answer is $x=-\frac{50}{8}$ and $y=\frac{11}{2}.$

5 0

3 years ago

Two circles have the same radius. Complete the description for whether the combined area of the two circles is the same as the a

Elodia [21]

Answer:

see below

Step-by-step explanation:

A = pi r^2

If they have the same radius they have the same area

A two circles = pi r^2 +pi r^2

= 2 pi r^2

If we double the radius

A = pi (2r)^2

= pi 4r^2

The combined area of two circles is 1/2 the area as the area of a circle with twice the radius.

5 0

3 years ago

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