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bazaltina [42]
2 years ago
9

Please help with math homework show workAll of the questions

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
3 0
At least do number 3 so I can help with the rest. That ok with you?

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If a city with a population of 700,000 doubles in size every 71 years, what will the population be 213 years from now?
hichkok12 [17]

Answer:

2,100,000

Step-by-step explanation:

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Helllp im doing my exam !
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log x ( 5 × 12 ) = 7

x^7 = 60

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7 0
3 years ago
PLEASEE HELPP!!!! ASAPP PLEASE PLEASEE!!!
Darya [45]

Answer:

two are correct:  side ED is equal to DC, and ABCDE is a pentagon

Step-by-step explanation:

pentagon is a polygon having 5 sides

You can find the length of BC by using the distance formula

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3 years ago
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Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=
Debora [2.8K]
The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
3 0
3 years ago
Please help me i need this answer asap ​
xxTIMURxx [149]

Answer:

No

Step-by-step explanation:

d = (x_2 - x_1)^2 + (y_2-y_1)^2

If any two points on  both triangles have the same measure then they are congruent.

41

52

3 0
2 years ago
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