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goblinko [34]
2 years ago
9

How old were the twins who played in the recital?

Mathematics
1 answer:
inna [77]2 years ago
3 0
To find out how old the twins were that were in the recital you need to be able to interpret a stem and leaf plot.  The number of the left gets placed with each number on the right to create a number in the data set.  See the key for an example.  This means there were 2 people that were 5 years old making them the twins!
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What fraction of 1 qt is 3 cups
cestrela7 [59]
The answer is to this is 3/4
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Below is the graph of f ′(x), the derivative of f(x), and has x-intercepts at x = –3, x = 1 and x = 2. There are horizontal tang
guapka [62]

the derivitive is just the slope

minimum happens when the derivitive goes from negative to positive, imagine a slope of the function, the minimum is where the slope goes from neative to positive, and to get there, it has to pass through 0

max happens when the derivitive goes from positive to negative

increaseing is when the derivitive is positive



so, based on what you said, the slope of f(x) is 0 at x=-3, x=1 and x=2 since those are where the derivitive is 0 (derivitive is just the slope)

A and B are wrong because the derivitive isn't 0 at those points

C is correct because increasing means that the derivitive is positive, and so therefo since the only hoirontal place in between 1 and 2 is 1.5, it must remain positive throughout and not dip down, C is right

D is wrong then




answer is C
5 0
3 years ago
Plsss help me ( I put a picture up )
Minchanka [31]
I'm pretty sure the 3rd one is right, use a calculator
3 0
3 years ago
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HELP ME!!! ITS DUE TOMMOROW!! Find the largest value of $r$ such that $6r^2+7r+8=6$.
Alex787 [66]
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0

Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)

we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c

so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12

split into the + and - for 2 answers
(-7 + 1) / 12
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-1/2

And
(-7 -1) /12
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But but it says largest so -1/2
4 0
3 years ago
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Please help me w the answer
evablogger [386]

Answer:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

\frac{()}{(x-4)(x-5)}

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ((x - 6)(x-10)). Now one has this much of the function assembled

\frac{(x-6)(x-10)}{(x-4)(x-5)}

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

6 0
2 years ago
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