Hello!
The volume of a cone is found by using the formula: V = 1/3πr²h.
Figure 1 --
From figure one, it shows us the radius, which has a length of 8 centimeters, and the height, which is 14 centimeters. With that values, we can substitute those values into the formula and solve.
V = 1/3π(8)²(14)
V = 1/3(64)(14)π
V = 64/3(14)π
V = 896/3π centimeters³, 938.29 centimeters³ (multiplied by π), and 937.81 centimeters³ (multiplied by 3.14).
Therefore, the volume of the first cone is 938.29 centimeters³.
Figure 2 --
From the second figure, the height of the cone is 19.6 and the diameter is 12. To find the radius, divide the radius by 2, which is will give the radius.
V = 1/3π(6)²(19.6)
V = 1/3(36)(19.6)π
V = 12(19.6)π
V = 235.2π, 738.53 (multiplied by 3.14), 738.90 (multiplied by π)
Therefore, the volume of the second cone is 738.90 units³.
Answer:
1 D
2 A
3 C
4 A
5 C
6 is supposed to be 35 so maybe choose the one closest
7 C
8 C
12 A=8/9
12 B=26/52
2/52
4/52
13/52
My apologizes but I cant read the graphs or the fractions down below
hope this helped :)
0.1
best of luck
hope i helped :)
This question is incomplete
Complete Question
Leah is creating satin bows for a wedding. From a 15-meter-long ribbon, she first cuts a piece 3 4/9 meters long. Then she cuts a piece 6 5/9 meters long from the remaining ribbon. How much ribbon does Leah have left?
A.) -12 meters
B.) -5 meters
C.) 5 meters
D.) 12 meters
Answer:
C.) 5 meters
Step-by-step explanation:
From a 15-meter-long ribbon, she first cuts a piece 3 4/9 meters long. Then she cuts a piece 6 5/9 meters long from the remaining ribbon.
Step 1
3 4/9 meters + 6 5/9 meters
Least Common Denominator = 9
(3+ 6) + [ 4/9 + 5/9)
9 + [4 + 5/9]
9 + [9/9]
9 + 1
= 10 meters
This means, the total number of ribbons cut is 10 meters
The amount of ribbon Leah has left =
Initial length of ribbon - Amount of ribbon cut
= 15 meters - 10 meters
= 5 meters
Hence, Leah has 5 meters long of ribbon left
