You have to use implicit derivative
dy / dx = y'
xy^3+y=3x
y^3 + 3xy^2 y' + y' = 3
[3xy^2 + 1) y'= 3 - y^3
3 - y^3
y' = ----------------- <-----------answer
3xy^2 + 1
Answer:
-30a⁵b + 12a⁴b² + 16a³b² - 4a²b⁴ - 2ab³
Step-by-step explanation:
( - 6a³b + 2ab²)( 5a² - 2ab² b)
multiply the second parantheses by each term from the first parantheses.
-6a³b×(5a²- 2ab²b -b)+2ab×(5a² -2ab²b-b)
-6a³b× (5a² - 2ab² b) +2ab × (5a² - 2ab² b)
-30 a⁵b + 12a⁴b² + 6a³b²+ 10a³b² - 4a²b⁴ - 2ab
combine like terms
-30a⁵b + 12a⁴b² + 16a³b² - 4a²b⁴ - 2ab³
Answer:
$ 25.26
Step-by-step explanation:
x = premium membership - diffrence between premium membership and standard membership
x = 41.25 - 15.99
x = 25.26
Answer:
32
Step-by-step explanation:
2*2=4 2^2
2*2*2=8 2^3
2*2*2*2=16 2^4
2*2*2*2*2=32 2^5
I hope this helps!
Answer:
Step-by-step explanation:
Put the values of x and y in the equations and solve the resulting system.
A(2) +(-3) = 5
A(2) +B(-3) = 20
__
The first equation tells the value of A:
2A = 8 . . . . add 3
A = 4 . . . . . .divide by 2
This and the second equation tells the value of B:
(4)(2) -3B = 20
-3B = 12 . . . . . subtract 8
B = -4 . . . . . . . divide by -3
The values of A and B are 4 and -4, respectively.