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4 years ago

Factor completely. 5x^2 + 10x - 40

Mathematics

2 answers:

Gala2k [10]4 years ago

6 0

Answer:

5(x + 4)(x - 2)

Step-by-step explanation:

Start by factoring 5 out of all three terms. We then have

5(x^2 + 2x - 8), or

5(x^2 + 2x - 8), which is in proper quadratic form.

Note that (4)(-2) = 8 and that 4 - 2 = 2, which match the 3rd and 2nd coefficients of x^2 + 2x - 8.

Thus, in completely factored form, we have 5(x + 4)(x - 2)

lesya692 [45]4 years ago

3 0

Answer:

5 (x -2) (x +4)

Step-by-step explanation:

5x^2 + 10x - 40

Factor out a 5

5(x^2 +2x-8)

We can then factor inside the parentheses

What two numbers multiply to -8 and add to 2

-2*4 = -8

-2+4 = 8

5 (x -2) (x +4)

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Evaluate the expression when x-3<br> 4x2 - 14x + 4

Lady_Fox [76]

Answer:

Step-by-step explanation:

Evaluate 4 x^2 - 14 x + 4 where x = -3:

4 x^2 - 14 x + 4 = 4×(-3)^2 - -3×14 + 4

(-3)^2 = 9:

4×9 - 14 (-3) + 4

4×9 = 36:

36 - 14 (-3) + 4

-14 (-3) = 42:

36 + 42 + 4

| 1 |

| 4 | 2

| 3 | 6

+ | | 4

| 8 | 2:

Answer: 82

6 0

3 years ago

What is 4 6/8+11 1/3

aivan3 [116]

So 4 6/8= (32/4)+6/8=38/8
11 1/3=(33/3)+1/3=34/3
so 38/8+(34/3)

to add you must get the bottom number equall so

114/24+272/24=386/24=16 1/12

6 0

4 years ago

Read 2 more answers

Factor the four-term polynomial.

Travka [436]

Group like terms , factor out common variable.

(xz+x) + (yz+y)
x(z+1) + y(z+1)

factor out (z+1)

= (z+1)(x+y)
= solution C.

6 0

4 years ago

CAN SOMEONE HELP ME WITH THESE QUESTIONS PLEASE!?

sukhopar [10]

Answer:

Step-by-step explanation:

$(c+9)^2=64=8^2\\$

c+9=±8

either c=8-9=-1

c=-8-9=-17

so c=-1,-17

8x^2-3=2

8x^2=5

$x^2=\frac{5}{8}=\frac{10}{16}$

$x=±\frac{\sqrt{10}}{4}$

so A

$x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2 ±3\sqrt{2}$

so D

8 0

3 years ago

Given cos ⁡ ( θ ) = 5/6 , then sin ⁡ ( θ ) = a/b .<br><br> Determine the values of a and b.

slega [8]

Answer:

a = √11 and b = 6

Step-by-step explanation:

Refer to attached picture for reference

for an right triangle with angle θ

we are given

cos θ = 5/6 = length of adjacent side / length of hypotenuse

hence

adjacent length = 5 units

hypotenuse length = 6 units

the missing side is the "opposite" length which we can find with the Pythagorean equation. in our case:

hypotenuse ² = adjacent ² + opposite² (rearrange)

opposite ² = hypotenuse ² - adjacent ²

opposite ² = 6² - 5²

opposite = √ (6²-5²) = √11

sin θ = opposite length / hypotenuse (substitute values above)

sin θ = √11 / 6

hence a = √11 and b = 6

3 0

3 years ago